Homework Statement
A woman is wearing bifocals that have one-half of the lens with a power of -1.2 D and the other with a power of 1.8 D. A lens provides her with a far point set at infinity and other will give her a near point of 25 cm.
Where are her near point and far point WITHOUT her...
I am taking Electrodynamics this semester and we are doing the course with the aid of "david griffith's Intro to electrodynamics" there has been alot of word that the course is extremely difficult... can anyone tell me ways to prepare for it?
wow thank you so much for telling me this in detail. I appreciate it very much... did you go to graduate school as a physics student? and are telling me from first hand experience?
Hello,
I am a undergraduate Physics student and I heard that if you pursue a graduate degree in Physics for grad school (not undergraduate) the department pays your tuition for you?
Is this true? I have 5 friends that they have finished undergraduate physics (payed their OWN tuition) but...
Okay... I think I found the solution
by using parametric equations
(t,0); (1,t); (t,1), (0,t) and plugging them in yields (0,0), (0,0), (t,t), (0,t) which makes it not 1 to 1. So... it gives me the triangle with those vertices. is this correct?
Homework Statement
Let D* = [0,1] x [0,1] and define T on D* by T(x*,y*) = (x*y*, x*). Determine the image set D. Is T one-to-one?
Homework Equations
The Attempt at a Solution
Okay... So I know it is not one to one, if you take out the point (x=0) then it is one-to-one, so you...
Okay... so I took your advice.
so I thought about what you said
so T(u,v) maps u => -u^2 + 4u
and v to v
so for u [0,1] is the interval... so that means [0, -1+4] = [0,3]
for v [0,1] goes to [0,1]
[0,3] x [0,1] so that means... it maps the square into a rectangle.
But...
Homework Statement
Let D* = [0,1]x[0,1] and define T on D* by T(u,v)=(-u^2+4u, v). Find the image D. Is T one-to one
Homework Equations
The Attempt at a Solution
I have no idea... I don't know how to do it.
The solution is [0,3] x [0,1]... yes it is one to one.
am I supposed...
Can anyone tell me the general procedure in doing the following procedure?
f(x,y)=xy^2 with domain x^2+y^2\leq4
Find it's absolute max & absolute min.
Okay, here is my thought procedure, tell me what I can fix.
So I would basically say, find the partial derivatives with respect to x and y...
What are the equations that describe simultaneity, and hey don't be afraid to throw some math out there. All though I might not be able to grasp things like the Ricci Curvature just yet, I could still derive the equations for Time Dilation & the Lorentz Contraction, so please show me the math, I...
Okay, so I was sitting in my room wondering about the differential operator D. Like for example, solving the equation
y\prime\prime+5y\prime+4y=0
introduce D=\frac{d}{dx}
(D^2+5D+4)y=0
so you can solve it by doing D=-4, D=-1
e^-^4^x+e^-^x is the solution
But how the hell do you solve...
Me and my friend Syl consistently talk about Special Relativity and it's effects in nature when electrodynamic bodies move at relativistic speeds. I wanna make a discussion.
What is Special Relativity?
How does it work?
How much do we understand?
\int\int(yx^2dydx)-2\int\int(xy^2dydx)
\int[\frac{1}{2}y^2x^2]=\int(-2x^2dx)=[\frac{-2}{3}x^3]=\frac{-54}{3}
-2\int\int(xy^2dydx)=-2\int[\frac{1}{3}y^3x]=-2(-12)=24=\frac{72}{3}
=\frac{72}{3}+\frac{-54}{3}=\frac{18}{3}=6
is this okay?
How did you get that solution besides canceling things out?
Cause, this is like a very annoying class, like what method did you use? Did you use p\equiv{y}\prime
Okay, objection 1 makes no sense... but I'll give you you're right for objection 2.
Here's what the textbook says for case 1:
y\prime=p, y\prime\prime=p\prime\mbox {Dependent variable y missing}
Saying that gravity should be ignored from the quantum level and should only be considered with \geq atomic, doesn't make much sense. Because atoms consist of nuclei and other smaller quantum subatomic particles...which all together work together and has a gravitational interaction, although...
Solve the Differential Equation 2yy\prime\prime+2xy\prime=0
set p=y\prime, and then it becomes case 1 in the textbook
Can someone please help me solve this? It's a night mare
I'm having trouble setting up this solution can anyone give me a hint, or set it up, so I can see if what i'm doing is right?
xy\prime=y=e^x^y
using the substitution
u\equiv(xy)
I figured out how to do that integral, the steps are as followed
(1) \int\frac{1}{1+\cos(u)}
(2) use \cos(u)\equiv1-\cos^2(\frac{u}{2})
and then it simplifies to
(3) \frac{1}{2}\sec^2(\frac{u}{2})
which comes out to
(4) \frac{1}{2}tan(\frac{x+y}{2})=y
Okay, but I still don't know how to find that integral, which is what I'm gonna go find out now. In the end I still learn something, even though I got the answer, I need to show my work completely, what's an answer without an explanation? a meaningless number...