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    How to rationalize the numberator?

    \frac {\sqrt{x}-3}{x-9} Multiply: Both {x-9} and {\sqrt{x}-3} By the conjugate of {\sqrt{x}-3} which is {\sqrt{x}+3}. \frac {\sqrt{x}-3( \sqrt{x}+3)} {x-9( \sqrt{x}+3)} From here, you should be able to do some algebra, to rationalize the numerator. Do you know what a...
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