Homework Statement
log2(x+2)=log2x2
-log base 2(X+2)= log base 2 (x2)
The Attempt at a Solution
I know the answer is supposed to be -1 and 2, but I get the wrong answer every time I try.
I tried bringing log2x2 over to the other side and then got log2(2/x) which got me nowhere...
oh sorry...here it is:
When one spins a ball in a circular path which has a radius of 2.25 m, what is the slowest speed of the ball at the bottom which will just make it around at the top of the path?
Homework Statement
A ball has a radius of 2.25 m. What is the slowest speed of the ball at the bottom which will just make it around at the top of the path?
The Attempt at a Solution
I dont even know where to start with this problem. I dont understand it. Any help would be greatly...
Homework Statement
A rock is thrown at an angle of 17 degrees above the horizontal at 28.5 m/s, from the ground.
a)How high will the rock rise above the ground?
b)What is the horizontal speed of the rock at the top of its flight?
c) How long will it take the rock to reach a vertical...
ok I get that one! you would get cube root of 7^3...so you would get 7. thanks I get that one now!
and back to the first problem. in exponents I think it would be:
(X3/4 * X1/5)-2
So if anyone wants to help with this one...so far I still have the wrong answer, I have no idea what I'm...
Homework Statement
(cube root \sqrt[]{}x^4 * \sqrt[]{}x^5)^-2
Honestly, I tried and my answer didnt make any sense...The answer is supposed to be 1/(x^23/3)
How would I go about solving this? Any help would be appreciated :)
Also how would I solve the cube root of 7 * the cube root of 49?
Ok, so what you're saying is that the applied force equals the friction, in this case. I thought it wouldn't move though if that was true? I'm just confused on this concept.
But anyway, using that information, frictional force=coefficient of friction x weight...
Homework Statement
If a force of 150 newtions is needed for a 600 newton weight to overcome friction, what is the coefficient of friction?
The Attempt at a Solution
I'm really confused, I drew a force diagram but it didnt help. I know I need to get the frictional force to solve for the...
Homework Statement
If a force of 45 newtons is needed to overcome friction and the coefficient of friction=0.26, what is the mass of the object?
The Attempt at a Solution
So would I need to find the frictional force first? But then I can't use the equation: (frictional...
Homework Statement
A 20 kg block is on a surface where the coefficient of friction is 0.30. Find the minimal force needed to have the block more slowly at a constant speed.
The Attempt at a Solution
So I did coefficient of friction(mass)(gravity)=frictional force
20(0.3)(9.8)=58.86...
Homework Statement
A fishing hooks a 2 kg fish on a line that can only sustain a max of 38 N before snapping. At one point, the fish pulls back with a force of 40 N. What is the min acceleration with which you must play out the line during this time to keep the line from breaking?
The...
Homework Statement
Acceleration of a car is -12.2 m/s/s. The car has a mass of 925 kg. Find the frictional force.
The Attempt at a Solution
So A=-12.2, M=925 kg
Fnet=MA
=925(-12.2)
= -11285 N
Fg=mg
=925(9.8)
=9065 N
Since there is no vertical direction...
So one of my problems is the square root of 768/square root of 384. I tried multiplying it by the square root of 384/square root of 384, but i ended up with a crazy answer. Should I simply the radicals first and then try it?....never mind, I divide radical 768/radical 384 to get radical 2...
I understand that the square root of (for example)j^16 is j^8. But when you have an odd squared root, like the square root of j^19, would it be j^9square root of j?
Another quick question 12 radical 36 would be 72?
Sorry, I know this is basic algebra, but I really have forgotten how to do...
The mass is constant, and there is a varying force. So would the mass be the dependent value(y-axis) and the acceleration be the independent value(x-axis)?
I think the mass is the dependent value so when I graphed it the line went straight across(horizontal). Is this right? I'm really...