Okay, I found the formula IE=RI^2+IL(dI/dt) and I used that to solve (b), which turned out to be 19 W, but that formula didn't work when I tried it on (c). I think what I have to do is find the total power in the system and subtract my answer from (b) from that. But I'm not sure. Any suggestions?
An RL circuit in which L = 9.00 H and R = 5.00 is connected to a 24.0 V battery at t = 0.
(a) What energy is stored in the inductor when the current is 0.500 A?
(b) At what rate is energy being stored in the inductor when I = 1.00 A?
(c) What power is being delivered to the circuit by the...
Okay, so what you said got me thinking, and I remembered that the time constant equals 1/t and that equals L/R so I set 1/1.4 = L/0.3 but that didn't work. Am I on the right track?
P.S. is inductance negative?
[SOLVED] Inductance RL Circuit
Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.
I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would...
Can anyone help me with this problem?
In Figure P22.31, the current in the long, straight wire is I1 = 8.00 A and the wire lies in the plane of the rectangular loop, which carries 10.0 A. The dimensions are c = 0.100 m, a = 0.150 m, and = 0.350 m. Find the magnitude and direction of the net...
A sphere of radius 2a is made of nonconducting material that has a uniform volume charge density . (Assume that the material does not affect the electric field.) A spherical cavity of radius a is now removed from the sphere, as shown in Figure P19.62. Show that the electric field within the...
Also, the problem defines L as the horizontal aspect of the triangle. Can I use the small angle theorum to assume that the hypotenuse is the same as the horizontal component?
I've never seen that kind of equation before, except in the equation A=[F/m]/(sqrt(w2 - (k/m)2) , which turns into something kinda similar when you solve for w.
Also, what is the "d" in md^y/dt^2 = -2Ty/L?
A ball of mass m is connected to two rubber bands of length, L, each under tension T, as in Figure P12.49. The ball is displaced by a small distance y perpendicular to the length of the rubber bands.
(a) Assuming that the tension does not change, show that the restoring force is -2yT/L ...
[SOLVED] Dampened Oscillations Problem
A pendulum of length 1.00 m is released from an initial angle of 15.0°. After 1200 s, its amplitude is reduced by friction to 5.5°. What is the value of b/2m?
How do you do this one? I know it has something to do with the formula w= sqrt(W0^2 -...
[SOLVED] Pendulum Oscillations Problem
A very light rigid rod with a length of 0.500 m extends straight out from one end of a meter stick. The stick is suspended from a pivot at the far end of the rod and is set into oscillation.
(a) Determine the period of oscillation. (Hint: Use the...
How do you find the electric potential energy of a hydrogen atom using the Bohr model? I tried doing U<sub>E</sub> = K(q1)(q2)/r, using the charge of an electron and the charge of a proton for q1 and q2 and using the Bohr radius for r, but that didn't work. How do you do this? (P.S. the answer...
I got the second problem so thanks for that, but the first one is still giving me trouble. I set the two equations equal to each other. The 60 kg and G both canceled out so when I cross multiplied I got 700kg(r2)^2 = 200kg(r1)^2. Then I used the equation r2=0.7 m -r1 and substituted that in for...
Problem 1:
I tried setting them equal, but then you get (G*700*60)/r^2 = (G*200*60)/r^2. You can't solve for r since they cancel each other out. Am I doing something wrong?
Problem 2:
How do you solve for field strength? Is it just the force divided by the mass? If 9.8 m/s^2 equals 9.8...
I have two problems: can anyone help?
First Problem:
A 200 kg object and a 700 kg object are separated by 0.700 m.
(a) Find the net gravitational force exerted by these objects on a 60.00 kg object placed midway between them.
(b) At what position (other than an infinitely remote one) can...
Okay, first I figured out the initial rotational velocity by using a=R(omega)^2, using 90m for R and 9.8 m/s^2 for a.
Then I figured out the total initial moment of inertia by doing I + 150(M)(R)^2
I used those to figure out the angular momentum by doing L=(I)(omega), using the I and omega I...
Homework Statement
A space station shaped like a giant wheel has a radius of 90 m and a moment of inertia of 4.50 108 kg·m2. A crew of 150 are living on the rim, and the station's rotation causes the crew to experience an acceleration of 1g (Fig. P10.47). When 100 people move to the center of...