i have a question that I cannot solve;
Show that the rms velocity of a sodium atom moving in a vaccum chamber at 300 kelvin is about 570 metres per second
pV=nRT and 3pV=Nm<c^2>
Define I(n) by I(n) = integral of x^n / square root(1+x^2) dx. Evaluate I(0), I(1) and then establish the reduction formula I(n) = ((root2)-(n-1)I(n-2))/(n) for suitable values of n, which should be stated
Here is my attempt
I found I(0) first,and got the answer to be...
1. integrate 1/(1+(xx-1)^0.5)
I.E. Integrate 1 over the sqaure root of( x^2 - 1)
2. I started by rationalizing the fraction and then i split the equation into two. I THEN let x = root2 (tanh(u)) for the 1/(xx-2) fraction, and have no idea what to do from there :S
1. The base of a cloud has an area of 2*10^7 metres squared and is on average 1km above the ground. treating the base of the cloud, the ground and the intervening air gap as a parallel plate capacitor, calculate the capacitance.[relative permittivity of air = 1.0]
2. I tried to say C...
I have a few questions:
1. 'small smoke particles in air are seen under a low magnification microscope to move randomly at a speed of 0.10mm/s. The speed of sound in air is 330m/s. Estimate the mass of the smoke particles.
I cannot make the link between speed of particle and speed of sound -...
I am stuck on a question about standing waves:
'The diagram below show's Melde's experiment and demonstartion of a stationary wave on a string'
The string has 3 full wavelengths shown, and 3 points are marked:
Point A is on an antinode, Point B is on the same antinode, but very...
Hello,
I have studied X-ray emission when an electron beam is fired at a tungsten target - But when I was presented with the graph of Intensity versus wavelength, I was confused...
I saw a curve, and on it there were spikes. What are these spikes, and why are they caused?
Something to...
Hi,
I have a question concerning a hydrogen spectrum:
There are 4 energy levels drawn:
Starting from the top
-1.4 * 10^-19 Joules
-2.4 * 10^-19 Joules
-5.4 * 10^-19 Joules
-21.8 * 10^19 Joules
1st question:
Going from the second level to the third from the top (from -2.4 to...
Yes, I have got the horizontal speed to be 3.5 metres per second
The vertical speed is 11.5 metres per second
But what trignometric function? I do not know of any which can predict the vertical entry angle of a perabola
Oh! That seems right - thank you very much!
One last question - how do you calculate 'the angle which the diver makes, to the vertical, upon entry to the water' ???
Thank You, again
Ah! That makes much more sense! Thank You
Finally, make I ask you - how could you calculate 'the angle which the diver makesm to the vertical, upon entry to the water?'
Ok, but he has water beneath him for all 8 metres.
The question does not say that he runs 6.5 metres and then falls, it says he travels 8 metres in the air...
So i am not sure
Thank you! That gives the correct answer.
But I have one question - If it takes 2.3 seconds to travel 8 metres, and takes 1.87 seconds to travel 6.5 metres - then why is the answer not 1.87? Since the time above the rock is the time taken to travel 6.5 metres, right?
I agree - but I do not appear to get the answer of 0.44 seconds.
This is how I did it -
If t = 2.3 seconds
Speed = d/t =8/2.3 = 3.5 metres per second
Assuming velocity remains the same (which it does), then to travel 6.5 metres will take :
T = d/s = 6.5/3.5 = 1.87 seconds.
What...
Hi - It is my fault - I have phrased it poorly.
The Diver takes off and travels forward 8 metres, by the time he has hit the water - however, 6.5 metres of the 8 is covered above the rock. The other 1.5 metres is covered as he is now falling down past the rock.
A cliff diver takes off horizontally from a cliff face 26.5 metres above the surface of the water. In the course of his flight, he travels 8 metres forwards, of which all but the last 1.5 metres of horizontal motion is above rock. In other words, he travels 6.5 metres in the air horizontally...
Yes, but I am not sure why this photoelectric emission will soon stop occuring...?
maybe the UV radiation will ionize the surrounding air, so charge is more easily removed??
If ultraviolet radiation is shone onto a freshly-cleaned zinc cap of an uncharged leaf electroscope, explain why the emission of electrons will soon stop
I understand it is about the photoelectric effect, but I am not sure why the emission will ever stop...
Thank You in advance!:biggrin: