yIII+yII-yI-y = 0
I used the characteristic equation and got:
r3+r2-r = 0
r (r2+r-1) = 0
Which means that r = 0 is one root,
And the other factors from the polynomial are (-1-Sqrt(5))/2 and (-1+Sqrt(5))/2
This means that the final answer would be:
y = C1 Exp(0x) + C2 Exp((-1-Sqrt(5))/2) +...
I know that sin2x + cos2x = 1, and I've tried that, but im still not getting it
C22Sin2(x)=-C33Cos2(x)
C22(1-cos2(x))=-C33Cos2(x)
C2(2-2cos2(x))=-C33cos2(x)
but this doesnt simplify into a constant solution, as far as i worked it out
I have to find a non-trivial, linear combination of the following functions that vanishes identically.
In other words
C1f + C2g + C3h = 0
Where C1, C2, and C3 are all constant, and cannot all = 0.
f(x)=17
g(x)=2Sin2(x)
h(x)=3Cos2(x)
I figure C1 = 0, because there's really no constant...