You know that the mass of the astronaut has to be the same on any planet. You have the weight of the astronaut on earth given to you. You know the acceleration of gravity. Use the second law of newton to find the mass of the astronaut first.
P.S : This question should be under introductory...
Ahhh I don't like it either. I will never trust windows calculators from now on. Microsoft should just burn in hell.
s = \frac{1}{2}at^2 = 8a
s = s_0 + v_0t + \frac{1}{2}at^2
s = 8a + 4a * 50 = 208a
208a = 130 * 3.14
a_t = 1.9625 m/s^2
a_n =...
Wait, if that is the case, we didn't even need tangential velocity in terms of time, since the greatest normal acceleration occurs on the greatest tangential velocity, which is t = 4 seconds. Can you check this work for me?
s = \frac{1}{2}at^2 = 8a
s = s_0 + v_0t + \frac{1}{2}at^2...
The equation used to find the normal acceleration is
a_n(t) = \frac{(v_t(t))^2}{r}
But the velocity is increasing only until 4 seconds. Until then, the equation is
v_t(t) = a_t*t
After then, the velocity remains constant.
How do I associate this fact with the normal...
Ok so for the first 4 seconds
s = \frac{1}{2}at^2 = 16a
is the distance.
and from 4 seconds to 54 seconds
s = s_0 + v_0t + \frac{1}{2}at^2
Acceleration is equal to 0 at this point so
s = 16a + 4a * 50 = 216a
216a = 130m
a = 0.602 m/s^2
Is this really...
Homework Statement
An outdoor track is full circle of diameter 130 meters. A runner starts from rest and reaches her maximum speed in 4 seconds with constant tangential acceleration and then maintains that speed until she completes the circle with a total time of 54 seconds. Determine the...