The question:
How will the first reaction take place for instance? Is CH3S- the nucleophile? Will it be added to the oxygen and the other hydrogen(H+) get attached to the other oxygen, with the double bond shifting to the center(C2-C3)? If this is right then where will CN- will attack?
I have a bit confusion as I overlooked a few things(my bad):
I thought the given angular velocity(ω0) shouldn't change but here as in the solutions I see they're considering ω0 to change with ω = √(C/I) [as ω0= ωβsin(ωt)]! Please explain me a bit here.
Since this pendulum is spinning it is coming to rest and then going the opposite way(harmonic motion i mean) so there is some some force in the wire which causes it to accelerate in the opposite direction, and therefore there must be some angular acceleration, right?
Thanks, now I understand it! What are your views on the first equation [ ω=√(C/I) ]? That equation seems familiar to the other ones like ω=√(mgd/I), I'm confused on what exactly C means.
The question was:
I will also include the solution:
So, what is the justification of the first formula [ω=√(C/I)]? I know how to derive simple harmonic equations, this one as I guess is probably similar? But I cannot connect as to how C is used exactly.
And the second formula [ω'=ωβ], I...
So, can I conclude from this is that the charge will distribute in such a way that there will opposite charge along the patch facing the charge q such that the electric field by it(charge q) will not be expressed inside the conductor/block and the charge on the the other patch of the block will...
No. Until there is some charge in the cavity, I think.
Another clarification I wanted to make on the second para, first line(of the main question body):
Actually this line has typos in it and I regret for not checking will I was typing it. I wanted to type:
"I know the charges induced on the...
The charges are q1,q2 & q. P,Q,O1,O2 refer to positions only. This is a conducting sphere with cavities containing charges.
I'm interested in knowing how the charge should be distributed in the sphere. I know the charges induced on the charges of the sphere should be equal and opposite to the...
This is not a standing wave, but I'm confused as you said "if the wave is stationary";there are two types of waves- moving waves and stationary waves, right?
Since this wave is moving or its particles are, can I say there is a constant power across this string and is constant at any region(or point?) over the string as the energy transmitted is conserved?
I don't know I'm confused myself. It probably is asking about the difference in power at the points (my concepts regarding this is a bit shallow); I don't know this makes any sense either.
But, in simple terms the rope or string does carry some power ?
I've marked the right answers.
They mainly indicate at power carried by the particles being zero, and here is my doubt- why should it be zero? Shouldn't it have some definite value?
I do understand that the kinetic energy is max at the y=0 and potential energy is max at y=A, but I don't know...
All I knew till now is that by applying ampere's law the net magnetic field at a point is zero if it does not encloses any current.
For solenoids as I looked up, the derivation also uses ampere's law, however here the loop encloses current due to it's position which I've tried to show in the...
So, where is exactly ampere's law applicable? If the current is moving around the pipe (due to rotational motion as here), we cannot apply it? Does the current have to be perpendicular to the imaginary circle we consider in ampere's law?
Here, the correct options are A,D.
Solution:
I got A as answer as ∫ B.dl=µI. But, the answer to the question says that it is a solenoid and therefore Bx=0 for point P. Here I'm a bit confused. I know this system resembles a solenoid in some ways, then By must have some finite value, but...
The answer to this question are the ones I've marked as shown above.
But I'm confused as to how?
The first option is okay since it has a chiral carbon with no plane or line of symmetry and shows geometric isomerism too.
In the third option, the compound shows Geometrical isomerism but i fail to...
Well so it means we are only considering octahedral compounds here? Then it is always sp3d2 for Ni2+ compounds.
Then what are the energy levels involved in tetrahedral geometry, if they are not t2g and eg?
I did search for [Ni(NH3)4]2+ and found that people asking questions on whether it is para...
I was expecting Ni2+ to be present also in the answer as it can give dsp2 and sp3 configuration.
[Ni(CN)4]2- and [Ni(NH3)4]2+ have dsp2 and sp3 respectively, right?
I had made a silly error in calculating the sum of the series before which you mentioned; you are right indeed! I didn't visualize the expression could be like this!