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1. Help me with Surface intergral!

the problem is given exactly above, nothin say about first obtant (i also thought about 1st obtant, too when i read the word "portion of", but it seems not that) so i guess the intergral is infinite is right, maybe the instructor gave the wrong problem. I wasn't sure so i asked, thank you for...
2. Help me with Surface intergral!

Homework Statement Evaluate \int\int (x^2 +4y + z)dS where S is the portion of the plane 3y +2z = 6 with 0<x<3 Homework Equations choosing x, y as variables dS = \sqrt{}(partial dz/dx)^2 + (partial dz/dy)^2 +1 The Attempt at a Solution If i choose x, y as variables or x, z as variables...
3. Intergral problem! !

got it! i didn't know that after spending 3 calculus classes, what a shame of me! thank you so much for your help and your time.
4. Intergral problem! !

I tried to do part and this is how i done (for the first intergral): u = x, du = dx, v = 1/2e^(2x), dv = e^(2x)dx uv - \int vdu 1/2xe^(2x) - \int 1/2e^(2x)dx 1/2xe^(2x) - 1/4(e^2 -1 ) x runs from 0 to 1, but 1/2xe^(2x) is not in the intergral part, so how to eliminate x? very...
5. Intergral problem! !

the first one xe^(2x) thing i guess it's intergral by part, but not sure
6. Intergral problem! !

Intergral problem! plz help! Homework Statement \oint(x: 0 to 1)\oint(y: \sqrt{}(1 - x^2) to e\overline{}x) xydydx The region bounded by y = e\overline{}x, y = \sqrt{}(1 - x^2), and x =1 3. The Attempt at a Solution i got stuck when i came to the part: 1/2 \oint(x: 0 to 1)...