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    Force of Friction Equation?

    I think the reason that my problems have arisen is because of my equation for the force of friction. I have Ff= ucosAngle That right?
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    Force of Object on Inclined Place

    I need extra help. I'm studying for my Final Exam which is tomorrow and I cannot remember how to find forces of objects on an inclined plane. The question I'm having troubles with is: A 12.5 kg crate is placed on a ramp that is at an angle of 22 degrees from the horizontal. Find the...
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    Final Exam Question Help

    Final Exam Question Help!!! HELP!! I need extra help. I'm studying for my Final Exam which is tomorrow and I cannot remember how to find forces of objects on an inclined plane. The question I'm having troubles with is: A 12.5 kg crate is placed on a ramp that is at an angle of 22 degrees...
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    Mechanics of a spring

    There is a question involving a simple land rover that can be controlled to go a certain distance. It is two pop bottles connected spout to spout and attached around the middle is a metal tape measure which one would roll up and then let go for the rover to move. I have to explain the mechanics...
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    Heat resistant and truly frictionless substance

    QUESTION If it were possible to make a tough, heat resistant and truly frictionless substance, what applications would it have? [?]
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    Puzzler Answer

    YES!!!! And I really have to thank you for being patient with my annoyance. I was a little bit annoying and I know it. So thanx. -Paige
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    Puzzler Answer

    Thank you soooooooooooooo much for everything!!! OMG THIS WAS SOOO FRUSTRATING. But thank you sooooo much!! -Paige
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    Puzzler Answer

    How did you get that for acceleration?
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    Puzzler Answer

    v-squared- = vo-squared- + 2aDelta X 4.163 -squared- = 0 + 2(5)a 17.330569 =10a a=1.733
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    Puzzler Answer

    K...I found acceleration wrong. I realized that. Acceleration = 1.733 m/s -squared- So then do I go F=ma F= 10.8 (1.733) = 18.7164 So is that Fnet? If it is...then what?
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    Puzzler Answer

    Ok...so I have that. But what is SOOOOO EXTREMELY FRUSTRATING...IS WHAT DO I DO AFTER I HAVE ALL THAT!! The acceleration becomes 0.4163 m/s-squared-. F= ma.... that makes is 10.8(0.4163)=4.49604 N that's no where near the answer.
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    I really need Help SERIOUSLY

    Ok....the puzzler. I haven't gotten really far. But this is what I have.... Vertical: Delta X= -12.96 m Vo= 0m/s a= -9.80 m/s-squared- v-squared- = vo-squared- + 2aDelta x v= 15.94 m/s v = vo + at t= 1.626 s Horizontal: Delta x= 7.5 m t= 1.626 s v= ? Delta x = vxt vx=...
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    Puzzler Answer

    Delta X = 5.0 m Vx= 4.613 m/s t =? Delta X = Vx(t) t= delta x/ vx = 5/4.613 = 1.083 s So do I add 1.083 to the previously establish 1.626 and then get 2.709 for total time?
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    Physics Puzzler!

    HELP!!!!! I am in grade 12 physics and my teacher gave us a puzzler for the weekend. I need serious help with it and all of my classmates cant figure it out either! The question is : A 10.8 kg box is 5.0 m from the edge of a 12.96 m high cliff. Bob pushes the box over the edge of the cliff by...
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    Puzzler Answer

    Ok... so I got vx to be 4.613 m/s. Then I use Pythagoras to find the velocity (vy-squared- + vx-squared- = v-squared) and I got it to be 16.59. Then to find acceleration I went: a= V/t = 10.20 m/s-squared- Am I going right...because then I get F= ma F= 10.8 (10.20) =110.19 N I don't...
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    Puzzler Answer

    The equations in the last one are a little wack. sorry... © = squared ¥Äx= delta x
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    Puzzler Answer

    What I did... I will show you what I did and then can you please tell me what I'm doing wrong. Consider Vertical: ¥Äx= -12.96 m Vo= 0 m/s a= -9.80 m/s v= ? t =? v©÷ = vo©÷ + 2a¥Äx v©÷ = 0 + 2a¥Äx = 2a¥Äx = 2(-9.80)(-12.96) = 254.016 = ¡î254.016 =15.93 m/s v =...
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    Puzzler Answer

    We were given the answer to this puzzler and its 71.96875 N
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    HELP Projectile motion and Force puzzler

    HELP!! Projectile motion and Force puzzler!! A 10.8 kg box is 5.0 m from the edge of a 12.96 m high cliff. Bob pushes the box over the edge of the cliff by applying a constant horizontal force to it until the box goes over the edge. The force of friction on the box is 49.0 N and the box lands...
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    Physics puzzler! Need serious help

    MORE HELP I did what the first post said to do and I still can't get it. I end up with Fnet= 117.504 N. What the hell am I supposed to do? I've spent hours on this problem and it's driving me crazy!!
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    Physics puzzler! Need serious help

    Physics puzzler! Need serious help!! HELP!!!!! I am in grade 12 physics and my teacher gave us a puzzler for the weekend. I need serious help with it and all of my classmates cant figure it out either! The question is : A 10.8 kg box is 5.0 m from the edge of a 12.96 m high cliff. Bob pushes...
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