The force and the impulse "average out"....not the energy usage.Are you able to understand the difference?
The fact is that fluctuations of the SAME force are more energy demanding.Why?I don't know and I don't care.The answer is irrelevant because is purely biological.
I could search at the...
This is total madness!!!
For God sake....you have the scientific proof and you admitted that you can't understand it!
It's YOUR claims that faster failure and greater energy usage equates greater impulse so it's YOUR job to prove it somehow.
You're obviously unable to do that(that would...
It's not a "debate".It's a guy with superhuman patience trying to teach you simple physics facts.
It's interesting only to see how far your obsession could go.
You have all the mathematical proofs that you're WRONG,you admit that you can't understand them,yet you still have the nerve to try to...
I have stated so many times why I think your examples are irrelevant that I'm sure it would be a waste of time to do it once again.But what the hell.....
I showed you studies that found that the greater fluctuations of the same average muscle force are more energy demanding.
For example,if the...
Here we go again!
NO...either you lift the weight up and down for a minute or you just hold it you use the same impulse and the same force per second.
It's irrelevant how fast you fail or what your EMG reads.
Not zero momentum....zero CHANGE in momentum.That's what the impulse represents.
For all the rest I don't have the patience.Just read carefully DaleSpam posts.
1,
Static hold = 480lb*s.
2,
Fast reps = 480lb*s.
3,
Slow rep = 480lb*s.
In all three cases the change in momentum is zero hence the average muscle force is equal with the weight.Impulse equals average force X time.In all cases is equal with 480lb*s.
The last five years you've...
:biggrin:...he just gave you an example on how to calculate the impulse when the force is constant...that doesn't mean that those values represent fast and slow reps!
Here's what required 21 pages of nonsense!
1)avg force=100N impulse=100N*s
2)avg force=100N impulse=600N*s
3)avg...
What kind of nonsense is that?
We talk about the average value of force for the exact reason that we recongnise that there're peak high and low fluctuations of force.Otherwise we would only talk about a constant velue of force.
BTW...the MMMTs are exctly the peak high of force.Those two are...
So stop your endless rambling and try to learn something.
With 100N
1)you do 1 rep with .5/.5
What's the average force?What's the impulse?
2)you do 6 reps with .5/.5
What's the average force?What's the impulse?
3)you do 1 rep with 3/3
What's the average force?What's the impulse?
For God's sake read carefully what we write if you want to learn something.How is it possible after so many pages to say a nonsense like that?
The average force will be the same either you lift the weight 1 or 100 times but the impulse will be 100 times greater if you lift the weight 100...
DaleSpam....I admire your effort to help Wayne but here's what I think that's the first thing that must be cleared out.
No matter what % of his force he deludes himself that he uses,he always uses force equal with the weight on average.....regardless the lifting speed.In his example.....he...
The numbers 1,2 and 3 are achieved with the "normalization" of the EMG data like it's described at the paragraph "analysis and treatment EMG data" at this study.
You can also see many force-time graphs where the impulse can be easily calculated.
Who agrees with that?The three of us are telling you that we both apply 80 pounds on average for 20 sec but for some reason you're unable to understand it.Your above example does not represent what happens in dynamic lifting where ALWAYS force equal with the weight is applied for the duration of...
OMG you're really delusional.You don't have a clue about basic physics terms and you think have proved something!ALL your nonsesnse from 1-7 show NOTHING in terms of force.
I won't repeat them....it's a waste of time.
For your own good....quit your nonsense and just focus on DaleSpam's...
Hi DaleSpam....if you have the time check the paragraph "2.1 Participants and experimental protocol" in http://jmbe.bme.ncku.edu.tw/index.php/bme/article/viewFile/635/839 [Broken].Do you think that the magnitude total muscle activation (TMA) can give a good estimation of the impulse?It's...
O.K. Wayne....so you claim that all the above somehow prove that more force per unit of time is applied for the fast reps.
The least thing you should do is to try to prove with physics that those variables have the effect you claim.You obviously can't even try because you lack of even basic...
sophiecentaur....I think that he first needs to grasp more simple things.For example...he doesn't seem to understand the meaning of average force.
Otherwise he wouldn't say nonsense like "...the forces don't make up..." or "...average means nothing in this debate...".
More important he would...
Either it's a muscle or a machine...one thing will always be for sure.
The muscle's/machine's impulse will always be equal with gravity's impulse regardless if the lifting is fast or slow for the same duration.The net impulse is always zero.
The same as always!You ignore everything that has been answered.
Let's redefine the question.You asked which lifting speed has greater effect of force over time(impulse) which in Wayne's world is defined as "total/overall force".
Everyone explained to you that the impulse is identical...
No Wayne....we will not forgive you for repeating yourself.You ask again the same nonsense ignoring all the answers.
For some strange reason you're unable to understand that it's impossible to use the 100% of your force for the whole set.Regardless if you lift fast or slow you use the same...
DaleSpam.....it doesn't have to be for over the whole rep.
Even if you examine separately the lifting and the lowering phase the average force is always the weight.In both phases the weight starts and ends at rest so the average acceleretion is always zero.
Unbelievable!!!You still can not get this!
YOU DON'T USE 100% FORCE FOR THE WHOLE 6 SECONDS.
You use more force than the weight when you accelerate and less force than the weight when you decelerate.For these 6 seconds....either you lift fast or slow....the average force per second is always...
....consequently,when the same average force is applied for the same duration the impulse is always the same regardless if you lift fast or slow or if you do more or less reps.
That's the whole story that took so many pages and so many threads.
That's the whole point of the discussion and it's been explained to Wayne many times.
Regardless if you lift the weight fast or slow for 30 seconds....the "total/overall" force is always the same and equal with gravity's impulse for that duration.
Hi DaleSpam,
he described the "total/overall force" as the effect of force over time so the ∫f(t)dt is exactly what he means.
.....and of course is the same regardless the lifting speed since the average force is the weight in any case.
Everyday you prove that you don't have a clue what everybody is trying to explain to you.
YOU DON'T USE 100% FORCE FOR 30 SECONDS.
You use more force than the weight when you accelerate and less force than the weight when you decelerate.For these 30 seconds....either you lift fast or...