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1. ### Could i get some help working out dy/dx of arccoth(x)

thanks for that I have the answer now
2. ### Could i get some help working out dy/dx of arccoth(x)

does that mean 1 = -1/sinh^2(y) * (coth(y))
3. ### Could i get some help working out dy/dx of arccoth(x)

sorry but I'm still not getting it, can you give me another hint or show me please
4. ### Could i get some help working out dy/dx of arccoth(x)

Homework Statement y=arccoth(x), find the derivative Homework Equations cothx - coshx/sinhx The Attempt at a Solution y = arccoth(x) x = coth(y) = cosh(y)/sinh(y) quotient rule = (sinh(y)*sinh(y))-(cosh(y)*cosh(y))/(sinh(y))^2 = sinh^2(y) - cosh^2(y)/sinh^2(y) x=...
5. ### Can someone me with an integral question

ive tried so many differnet ways for this and i still can't get it can someone please help
6. ### Can someone me with an integral question

let F(x) be the antiderivative of the function f(x) = -x sin (pi*x)-3cos(pi*x) such that F(0) = 0.Find F(1/2)
7. ### Another light question

Homework Statement monochromatic light of wavelength 616nm is incident on a narrow slit. On a screen 1.7m away, the distance between the second diffraction minimum and the central maximum is 1.8cm. What is the width of the slit in mm? Homework Equations The Attempt at a Solution...
8. ### Light question

Homework Statement A thin flake of mica (n= 1.58) is used to cover one slit of a double slit interference arrangement. The central point on the viewing screen is now covered by what had been the 9th bright fringe before the mica was used. What is the thickness of mica if light of wavelength...
9. ### Another sound question

thanks. I got the right answer...in the end. I was using a converter for the mach to meters a second conversation that's why i got it wrong. But thanks for the help
10. ### Another sound question

ohh, i didnt pick up on the rearranging error. Now I get the horizontal distance to be 5619.51223. Is that right. Then if i divide that by 442.5696 (which is mach 1.5) i get 12.70, but the correct answer is 11, am i still doing something wrong? do i use taht equation?
11. ### Another sound question

i still get the same horizontal distance. I use tan theta = opposite/adjacent, which i rearrange to tan theta x adjacent = opposite, so tan 0.73 x 5029 = 4500.54. Is that right because i still get the wrong answer
12. ### Sound question

thanks for the help. I got the right answer
13. ### Another sound question

i converted mach to meters a second but if i use 1/1.5 i get 0.73 degrees for theta. Using this i got 3171.18m for the horizontal distance. Now do i use time = distance/velocity, and if so do i keep the speed in mach or meters a second
14. ### Another sound question

i did that an got the angle as 0.8867. then i used tan-1 x adjacent equals opposite, which i had as the horizontal distance. Then i used time = distance/velocity but still get the wrong answer. Can you please help, am i still doing something wrong
15. ### Another sound question

Homework Statement A jet aircraft traveling with a velocity of mach 1.5 at an altitude of 5029m passes directly over an observer on the ground. How many seconds elapse before the observer experiences the sonic boom created by the jet? speed of sound= 343ms-1 Homework Equations The...
16. ### Sound question

Homework Statement Two loudspeakers face each other at opposite ends of a long corridor. They are connected to the same sourrce that produces a pure tone of 343Hz. A person walks from one speaker towards the other at a speed of 0.7ms-1 What beat frequency does the person hear? speed of...
17. ### A Force Question

so i have 1.64 from the first force i worked out and if i put the friction force into the work equation w= -0.2 x D i get -0.82. If I add the two works i have i get 0.82, but the answer is 1.3... can you give me hints on what I've done wrong??
18. ### A Force Question

could i put it as the force in the work equation and put the distance as the displacement that's stated in the question?
19. ### A Force Question

Homework Statement A force F=-4.3i+2.0j+1.5k Newtons exerts a displacement of d=-0.8i+1.8j+-3.6k metres upon a small (ie mass is negligible) object. If the friction force is equal to Ffr=-0.2,, then what is the net work done upon the object? Homework Equations The Attempt at a...
20. ### Force question

what do you mean by resolving the forces acting into their components that are parallel and normal to the incline
21. ### Force question

Homework Statement A 380kg piano slides 3.5m down at 27 degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of friction is 0.40. Calculate the force exerted by the man Homework Equations The Attempt at a...
22. ### Can someone elp me with a couple of homework questions im having trouble with

ive got the right answer now. I realize what i did wrong. Thanks for the help though
23. ### Calculate the magnitude of particle acceleration

ive worked this one out. Thanks for the hint
24. ### Can someone elp me with a couple of homework questions im having trouble with

i found this equation. R= v^2 sin 2 theta/g. If i put my values in there i get 2.23 x 10 ^4, the right answer is 1.28 x 10^-2. I am pretty sure this equation is the correct one, can you please give me hints on what I've done wrong?
25. ### Calculate the magnitude of particle acceleration

but do i still have to find the second derivative using this? Can you give me a hint on how to do this?
26. ### One other question i need help with please

finally got the right answer. Thanks for the help
27. ### Calculate the magnitude of particle acceleration

Homework Statement A particles position is given by r=42t^2i + 41t^3j + 6k. Calculate the magnitude of its acceleration at time t = 15 seconds Homework Equations The Attempt at a Solution to find the acceleration i found the second derivative which i had as 246t + 84. Then i put...
28. ### Can someone elp me with a couple of homework questions im having trouble with

so I used this equation to y=v^2y0-v2y/2g. I rearanged it using the values i had to work out vy0, which i got 32.56, i used the distance as y and v2y as 0. Then i put that into this equation vy0=v0sin theta, to work out theta. I rearranged it to vy0/v0 sin-1 = theta, i used my value for vy0 and...
29. ### One other question i need help with please

so now i have (0.73 x mg) which is the Normal force, then i have mg as the gravitational force so if i add those together do i get ma? Then if I rrearrange m to the other side does that cancel the other m's? and is that the final answer?
30. ### One other question i need help with please

dont pay attention to that last reply that was from before
31. ### One other question i need help with please

do i have to work it out using vectors? with that being the downward one

a vector?
33. ### One other question i need help with please

or do i do 0.73 x mg=ma then work it out?
34. ### One other question i need help with please

but what do i put as the mass value to work out a
35. ### One other question i need help with please

the normal force is equal to what it was originally multiplied by 0.73?
36. ### One other question i need help with please

doe sthat mean i put 0.73 as the mass and 9.8 as g? will the total of that be the acceleration
37. ### One other question i need help with please

equal and opposite forces? but i don't see how i can use the numbers given to get a numerical answer
38. ### One other question i need help with please

Thats all th information the question gave me. Using a force diagram i see that the sum of forces in the downward direction is 0 when the elevator is not moving and by my working out it says its 7.154 when it is moving down. I don't know if this is what you mean or if its right, I just tried to...
39. ### One other question i need help with please

one other question i need urgent help with please Homework Statement A person standing on a bathroom scale in an elevator notices that when the elevator starts to move their weight decreases to 0.73 of its original reading. What is the acceleration of the elevator? Homework Equations...
40. ### Can someone elp me with a couple of homework questions im having trouble with

Homework Statement A hunter aims directly at a target (on the same level) 54.08m away. If the bullet leaves the gun at a speed of 143.91 m/s then at what angle should the gun be aimed in order to hit the target? (answer in radians) Homework Equations The Attempt at a Solution Vx =...