# Search results

1. ### Superposition theorem

It looks to me like your second formula is still incorrect. You should keep the two currents going in the same direction. The first current is clockwise (although its easier to keep the signs straight if you go counter-clockwise in this case) so you get -2A as you said. In the second case...
2. ### Finding voltage using integral

If I did this correctly, I got a very nice even number - VERY even.
3. ### Rather simple diode problem

I would begin by assuming that D1 is conducting. If D1 is conducting then you immediately know the voltage across R2 since the voltage across an ideal diode is constant. From there you can calculate the current in each node. If D1 is not conducting, then the resulting currents and voltage...
4. ### Voltage divider question

Correct. Since there is no where for the current to flow through the 4k resistor, there is no voltage drop.
5. ### Engineering Circuit analysis

Sink current means current going into the voltage source. Source current means current going out of the voltage source. The node I am talking about is the point where the voltage source and current source meet. A current source will force 3A and put no constraints on the voltage. Likewise...
6. ### Engineering Circuit analysis

That would be true if the 20V supply was not there. But being an ideal voltage source, it will sink or source current in order to keep the node at 20V.
7. ### Voltage divider question

Current through a resistor is needed to have a voltage drop. If there is current going through the 4k resistor, where is it going?
8. ### Sense Resistors

In a 4-wire (kelvin) measuring system, why are there "sense" resistors? I understand that because there is very little current on the sense line there is no voltage drop. What purpose do they serve?
9. ### Overshoot and the 10x probe

That helped a lot. Thanks for all the input. This is a great forum! http://photos.imageevent.com/crossfamily/campingatsunsetbay/large/ConsultClk_w_470ohms.PNG [Broken]
10. ### Overshoot and the 10x probe

As far as I know, fast edges are not important so I think this fix will be acceptable. I'll experiment with it tonight and report back. Thanks a ton.
11. ### Overshoot and the 10x probe

Ah yes, that makes sense. Hadn't thought of that. Okay, this is starting to make sense. So, would a possible fix be to add a 1k resistor to the output causing it to be loaded at all times? 1k load when turning on, 2k load when turning off.
12. ### Overshoot and the 10x probe

1k resistor on drain. I didn't think 150k was high enough frequency to worry about reflections although I know as the wire length increases, it's more likely to become an issue.
13. ### Overshoot and the 10x probe

Just noticed that my probe shows 115pF on 1x and 16pF on 10x. However, when I put a 22pF or 100pF cap to ground in parallel with my probe set to 10x, the overshoot increases??
14. ### Overshoot and the 10x probe

I'm working on a microcontroller project where I'm sending out a clock signal at 153kHz and then converting it to 0 to 12V levels using a n-channel MOSFET. The wires are approximately 2 feet long after the conversion. I was disturbed by the excessive overshoot I was seeing on my USB scope. I...