The surface on your 3D objecct that you apply current must be flush (in another word, must be on the same plane ) with the region boundary surface. The terminal surface cannot be contained inside the region.
In your case, you may have to extrude your terminal surface out to get to the boundary...
In Maxwell, for soft ferrite, you cannot use BH loop in maxwell. You need define the BH curve using the simple relation B = uH, starting from 0,0. The curve (or the date set) only reside at the first quarter, positive X-Y.
I don't have access to Maxwell and couldn't recall any details, but such kind of error sometimes indicates that due to the movement of your object, they are out of defined region. Try animation to see the movement, and see if all objects are still within the region after moving. I could be wrong...
Use the formula you mentioned above, and define the dataset "ds1". It cannot be a perfect rectangular wave form, you have to define a short period of time for rising and falling, such as 0.01s, depending on your frequency of the wave form. The dataset is more like, (0,0) (0.99,0) (1,1) (1.99,1)...
The last error is because the first error.
The first error, I am not sure but wonder if you have defined your solution region. In 2D simulation,the region is called balloon or something like that.
I believe you can only plot 2D rectangular curve, B along a line, and export the X-Y data. A plan will not show in the Geometry menu, only line or point.
You can plot B on a plane, like XY plane or any 2D plane you draw, but you cannot export that to a data table as that will be infinite number...
B value (H, J for the same) can be plotted along a line, or at a point for specific value.
In order to see the B value along a line, you need draw a line using the line tool. You can add a line as non model so you don't have to solve the simulation again. Once you add a line, go to Results ->...
There are so many details for each solution type. I can only make a general comment here.
If you want to evaluate high frequency current effects, involving skin depth, eddy current and so on, you have to use real 3D model and specify the conductor as solid. This means if you have 20 turns of...
Need to make correction.
Only when you assign Voltage excitation, then DCR value need to be specified or simulated. Because DCR value is needed to get current from the Voltage.
If the excitation is Current, then you cannot specify the DCR.
All above are only for Transient and the excitation...
Q1,
I would suggest to use the full model instead of 1/16th. The region will normally be a rectangular. When you cut the model into 1/16th, the region will be cut into the same shape because the coil current excitation surface need to meet with the region boundary. I haven't used other shape...
How is your input signal frequency? Will the current be uniformly distributed and skin effect can be ignored?
You might want to look at DC conduction solver. In DC conduction solver, you can specify 6 input terminals as Excitation, and then the final output terminal as Sink. You will see the...
Let me pretend I understand what you try to do.
My first thought is that you cannot create a such 3D model, as indicated by the error message.
I would assume it will be a lot easier to just create 6 individual model representing 6 windings. Each winding has its own input/output terminals.
By...
Your description is a little confusing to me. Not sure what version Maxwell you use.
In the General tab, you specify Stop time and Time step.
What you described below should be in the Save Fields tab.
You need make sure these time setup will be good for your input condition. What is the input...
Well, that is what stated in the HELP, A is only available to 2D.
In the HELP, look for Post Processing and Generating Reports -> Plotting Field Overlays -> Plotting Standard Field Quantities.
Simple thing first,
For the error message, second one is normal. You are using transient solution, so it tells you that only initial mesh will be used, meaning the mesh may not be fine enough, the result may not be that accurate, but, generally acceptable.
For the first error, do you have...
In transient solver, the mesh is only initial mesh. The field is not saved unless you specify to save them in the Analysis setup.
When you want to plot field overlays, you have to specify the time moment that has the field saves as defined in the above Analysis setup.
In Maxwell, most of time you don't draw the real winding (turns, layers and so on). You draw a 3D object and specify the cross section as stranded and define how many turns.
For core loss, I have not done much but here is what I believe.
The core loss data set in Maxwell is used to define Cm, X and Y three parameters (after fitting the loss curve). With these three parameters, the core loss is calculated at any give frequency when the simulation runs.
For...
You don't necessarily input extra inductance. The simulation will use the modeled inductance of the coil. Induced current will have 90 degree phase shift from the input voltage.
For the voltage excitation, you need input the coil resistance. The simulation will not model the resistance if the conductor coil is specified as stranded.
you don't need to know CAD or FEM to learn Maxwell, but you will need to learn how to draw 3D object in Maxwell. Knowledge on CAD or FEM will certainly help but not necessary to start to learn.
In the picture, I don't see coils on the core center leg. Do you have windings on the center leg?
I assume those two black long bars are what you called "iron tracks". If so, yes, you can drawing them by cylinder and assign voltage or current to them. And then obtain power loss in Maxwell.
I am not sure how much you understand about a transformer. Just by looking at the model, a few questions here;
You have an E core, but only half. Normal transformer need two E cores mating together to close the magnetic path without gap. Only half E core means a huge air gap.
You have orange...
In Maxwell, excitation is applied to an area which is a 2D object. Excitation cannot be on a line.
Calculate power is possible depending on how complicate your model will be.
Take a screen shot of your model and post it here. Let's take a look at your model.
Polyline is a line, not sure how you create a coil with that. Anyway, a coil needs to be a 3D object with volume.
Yes, you will be able to plot a rectangular plot for loss vs time in "Create Transient Report".
Ohmic loss only appears in calculator, I think. That is the I^2R loss in a...
The current is correct.
You can plot input current vs time to verify it is sine wave. Loss is not sine wave, you need take average value on the loss vs time curve. Make sure you plot solidloss if your copper is solid.
I don't have access to Maxwell until next week so cannot look at your project.
You can draw a ring in a few ways. You can also import a ring from SolidWork if you have someone else help you in SolidWork.
In Maxwell, you can draw a torus. You can also draw a circle and sweep around an axis to...
My suggestion is to draw a ring in Maxwell, assign copper to the material property, and go from there, to calculate the copper loss, stranded and solid, so you can get used to Maxwell.
After that, you can work on your real model, whether created in Maxwell or imported from SolidWorks.
Now let's talk about your project.
First, since your main interest is the power loss in the copper, so you may just ignore the core loss, and then you don't have to have core in your project. A simple air coil will be good enough.
Second, if you don't need to have a real model representing...
Before we talk about your project, and I assume you understand what is skin effect, here let's review it again.
In the following pictures, the circle represents the cross section of a solid round wire, with 2mm diameter. An AC current at 1KHZ, 100KHZ, and 1MHZ are applied to the wire. The color...
Let's start with what's in the real world and then take a look at what can be done in Maxwell that is close to the real world.
The follow picture is a ferrite RM6 core with 24 turns winding. This is a real inductor model, made by SolidWorks. I don't think Maxwell can create this model.
For...
Let's see the copper ohmic loss;
For DC, V=100V, R =5 ohm, we have I=20A, and power loss is 2000Watts.
For AC = 100* Sin(W*t), in this case, 100 is peak current, you need take the rms value for power loss, so Vrms = 70.7. For R = 5ohm, the power loss is , 999.70Watts.
In order to have the...
I have not done anything like this and may not be that helpful. But based on my understanding, a band object needs to be a sheet in 2D or a region in 3D without any interruption. The band object should not interfere with anything else. It is between the moving objects and the stationary ones...