The first part of the problem seems easy enough, the free electrons in the wire would move in a circle owing to an electric field that would be induced in the rod which would provide the centripetal force for the same (Please correct me if I am wrong). So we have $$eE=mω^2x$$, where e is the...
Here's a perspective on it: consider a hollow cylinder with a current flowing along its length, now consider a small element on this cylinder. It's easy to see that it would experience a force due to the other elements on the same wire. I like to think of this as a small element (which is...
Can't we use basic centrifugal force for this? My professor told me to think along these lines (we haven't done torque yet) and I just believe that I over complicated my explanation a bit, and that a centrifugal force is pushing the car outside.
Homework Statement
Why do the left wheels of a car rise when it takes a sharp left turn (that is it lurches towards the right)?
Homework Equations
$$a_c= V^2/R$$
The Attempt at a Solution
I started by imagining the car as being a part of a very large ring, dx.
Since it's taking a left turn...
This problem is fairly objective (though quite stupid)
What does î(o) represent?
Does it refer to a vector making angle 0 degrees with the x axis?
I searched but couldn't find the answer anywhere. Please help.
Moderator note: post edited and moved from hoemwork
Yes...that was what I wanted to know, because I had thought it would be a spiral but I didn't know the shape of it.Then I came across the logarithmic spiral, and it was the nearest shape that had come close to how I visualized the path. It was an intuitive guess, even though the parameters were...
And is there another equation that can give me the desired information apart from this differential equation, or do I have to depend only on the problem statement for the same?
The spiral I had mentioned was referring to a logarithmic spiral initially, before it attains a circular shape. More appropriately, it was a logarithmic spiral which terminated into a circle, because the radial component will keep on decreasing, and eventually it will become 0 otherwise in the...
That was not what I meant. By path, I meant the trajectory it adopts before it has attained the desired radius. After that, I had taken it for granted that the particles move in concentric circles ( in my book, there was a hint given which said that). So, you mean that it can either keep on...
So, it does follow the path of a spiral. What I wanted to know is how can you prove it mathematically.
But I want to know what happens even if it is only transiently zero, and the mathematical aspect of it too.
I believe it is the first one matching the trajectory of the circle( why is it SHM, though?), because eventually the particles probably move in concentric circles.
Sorry, I made an error.
$$u^2=(\omega r)^2+v_r^2$$
So now I got a differential equation of the form
$$\frac{dr}{dt}= (u^2-(\omega r)^2)^(\frac{1}{2})$$
And I'll solve it, with limits of R from 0 to ##R_u## with ##w=\frac{u}{R_u}##
Thanks a lot.
Also, for the problem of when it catches Q, maybe I...
As I said, by equating the angular velocities, I got the radius $$R_u=\frac{u}{v}R_v$$
And for equating the radial component with ## \frac {dr} {dt}##, do we have r here as ##2\pi R## or simply as ##R##
For your second observation ##u^2=\omega^2+v_r^2##
Do I use the above equation in the...
What I mean to say is P will move along a new circle with different components of angular and radial velocity having resultant u every instant. At that instant when it's radial velocity becomes 0, it will move in a circle
Homework Statement
Starting from the center of a circular path of radius R, a particle P chases another particle Q that is moving with a uniform speed v on the circular path. The chaser P moves with a constant speed u and always remains collinear with the centre and location of the chased Q...
Yeah @above is right. I didn't explicitly mention what the variables were referring to. Here by x, I didn't mean the horizontal displacement in the equation, but the general form by which such an equation is represented.
What I meant was
$$\frac{dh}{dt}\frac{dv}{dh}=a$$
But as the above...
It isn't x, is it?
That's the only other variable distance on which velocity depends.
On the other hand, do we have to integrate velocity w.r.t. Time to get that distance?
To me the second one seems more appropriate, but then how to we find time?
Which one to do, and why?
If you've ever played loop the loop, in the game, we have to give a ball some velocity (kinetic energy) initially so that it can complete the loop. It's the same principle here.
Say, your friend challenges you to make it to the top of the loop. You don't need to do the full loop, just reach the...
Homework Statement
To protect his food from hungry bears, a boy scout raises his food pack with a rope that
is thrown over a tree limb at height $$h$$ above his hands. He walks away from the vertical rope
with constant velocity $$v_b$$, holding the free end of the rope in his hands
(a) Show...