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I don't actually know what you mean by your last paragraph. How would you would the small bleed tube operate as a level sensor? Can you please explain how something like that might work?

Thanks for the advice. Your feedback was exactly what I was looking for.

I am trying to design a water vessel system that maintains it's water level as it is consumed. In item 1. It's a simple water barometer, where the height of water in the column can be supported by atmospheric pressure until 10.34. In item 2. There are two columns that are open to atmosphere...

Figured it out. (4 pi r^2)=P/I where r=46. P=4.2*10^-4

Homework Statement An enclosed chamber with sound absorbing walls has a 2.0 m × 1.0 m opening for an outside window. A loudspeaker is located outdoors, 46 m away and facing the window. The intensity level of the sound entering the window space from the loudspeaker is 42 dB. Assume the acoustic...

i think i got it. thank you very much zondrina!

Thank you! So you would run the central difference formula with 2, 1, 0.5. then for we would use f(2) and f(1) , and then again with f(1), f(0.5)? Maybe what confuses me is when they say "calculate the TRE of the last estimate", its just the second of two estimates calculated using Is it...

Homework Statement [/B] use richardson extrapolation to estimate the first derivative y=ln(x), x=5 using steps of 2, 1, 0.5. Four decimal points. obtain true relative error for the last estimate and comment on its value. Homework Equations [/B] deriv ln(x)=1/x The Attempt at a Solution I...

Thank you so much! That makes total sense!

Okay, I work this out to y_1=1/4 and y_2=1/2... which seems to fit in the equation... but I am still not really sure why the coefficients for the e^(-4t) don't seem to match the solution

I have not encountered this type of problem before. How do you go about finding the particular solution?

Homework Statement Consider the initial value problem for the system of first-order differential equations y_1' = -2y_2+1, y_1(0)=2 y_2' = -8y_1+2, y_2(0)=-1 If the matrix [ 0 -2 -8 0 ] has eigenvalues and eigenvectors L_1= -4 V_1= [ 1...

right... 3 roots... so r^3-r=0 r=0, r=1, and... r=-1 -1-(-1)=0 I always get stuck on the stupidest mistakes. I really appreciate it! thanks

Homework Statement If the method of undetermined coefficients is used to find a particular solution yp (t) to the differential equation y'''-y'=te^(-t)+2cos(t) should have the form: ? Homework Equations The Attempt at a Solution LHS r^3-r=0 roots= 0, 1 y_c(t)=c_1e^t RHS...

Got it... I was making a mistake with my derivative... I feel stupid. Thanks Mark44!

You add a coefficient t so the guess becomes At+B+Cte^(-t) right? When I plug that back in, it still cancels out

Homework Statement y''-y=t-4e^(-t) Homework Equations method of undetermined coefficients The Attempt at a Solution solving for characteristic equation first y''-y=0 r^2-1=0 c_1e^(-t)+c_2e^(t) RHS particular solution t-4e^(-t) y_p(t)= At+B+Ce^(-t) y_pt'(t)=A-Ce^(-t)...

Homework Statement A uniform ladder having mass 14kg and length 3m is released from rest when it is in the vertical position. If it is allowed to fall freely, determine the angle Theta at which the bottom end A starts to lift off the ground. For calculation assume the ladder is a slender rod...

Homework Statement During a sustained wind the blades on a two blade horizontal–axis wind turbine is turning with an angular velocity of 5 rad/s. If initially the blades have an angular velocity of 2 rad/s, determine the distance point P on the tip of the blade has traveled in 3.0 seconds...

Homework Statement If y=y(t) is the solution of the initial value problem { y'+(2t+1)y=2cos(t) y(0)=2 then y''(0)=? it is a multiple choice practice problem with choices y''(0)=2 y''(0)=-2 y''(0)=4 y''(0)=0 y''(0)=-4 Homework Equations The Attempt at a Solution Im really not sure how...

i always feel so stupid when i come on the site. yes it is the reciprocal. thank you for your help

Homework Statement Find the general solution: y'-3y=(y^2) Homework Equations The Attempt at a Solution divide both sides by y^2 y'(y^-2) -3(y^-1) = 1 we know v=y^(n-1) v=y^-1 v'=d/dx(y^-1) v'=-(y^-2) y' plug it back into y'(y^-2) -3(y^-1) = 1 -v'-3v=1 this is where I think I am...

sumF_y=0 N-mgcos30=0 N=17 N sumF_x=0 F_spring-F_friction=m_block*accel_block kx-uN=ma if static, accel=0 410(0.5)-u(17)=0 u=12.06 doesnt seem right... i think the x is wrong for the spring but i can't visualize it.

Homework Statement Practice problem for midterm. Homework Equations [/B] T_1+U_1=T_2+U_2 U_spring=1/2kx^2 The Attempt at a Solution [/B] Set X-axis along the 30 degree line and the Y-axis perpendicular. I'm not sure how to consider the friction constant into the formula. Any help is...

Thanks for your help. Sure is frustrating when you start doubting yourself. Take care.

(5i)^3+25(5i)= -125i+125i=0 (-5i)^3+25(-5i)= 125i-125i=0 0^3+25(0)=0 seems to check out for me. however this is not giving me the correct answer according to the solution

Homework Statement Find all zeroes for the function f(x) f(x)=x^3+25x Homework Equations The Attempt at a Solution I tried factoring out x out of it. x(x^2+25) and again to give x[(x+5i)(x-5i)] this would give me the 0,-5i,+5i as the zeroes. Doesn't seem to be right though. Any...

Can you calculate eigenvalues and eigenvectors for rotation matrices the same way you would for a regular matrix? If not, what has to be done differently?

S0 + identity matrix on left side... = [-4 0] ... then /2= [-2 0] -8 -6 ......-4 -3 GOT IT!

Homework Statement We are looking for the matrix A Homework Equations (A^transpose)^transpose=A The Attempt at a Solution i would start with finding the transpose of the matrix. -5 0 -8 -7

Thank you! So if the obstacle was taken away then 100% of the photons would end up being reflected-transmitted/transmitted-reflected and thus all ending up hitting the detector on the right. This is due to interference. Right?

If a single photon light source shoots a photon through the "attached" path. What is the percentage of the photon will make it to each detector. The light source is the box, the photon trajetory is yellow, beamsplitter is blue, mirror is black, detectors are purple, and obstacle is red. I think...