Or you can use a strategy that has been put forward in a book here recently in Norway. A guy who's world top at memorizing cards use two techniques: travelroute and images.
You use familiar places, like your home, and walk through each room. You'll recognize these rooms very well because it's...
(e^u)`*u` I'm making a fault here? no chain rule in integral? e^(x^2)=e^(x^2)? , but why isn't chain rule being used? (like in §e^(3x-2)dx=(1/3)e^(3x-2)+C.) it looks like it should, heh. And how do the x^2 dissapear..
Where do I find LaTeX?
Yeah, I meant chain rule. in is natural logarithm, e^inp=p.
My try went:
5/2§2x*e^(x^2)dx (cause here is where you 'use it', right? =
5/2*2*(1/(1+1))x^(1+1)*(e^u)`*u` (chain rule) =
Solve (e^(x^2))` , use this result to solve §5x*e^(x^2)dx
* is multiply
` is derive
3.§a^xdx=1/ina*a^x+C (a is a number)
The Attempt at a Solution
(I'm alittle confused as to...
uh, are you joking with me, or am I writing down the question wrong(cause I know I have a bad habit of not reading the question at probability well enough)? Cause that was the way I was thinking as you above.
Jeeserssweesers(for a lack of a better word), probability is confusing.
A family has three children, no twins or.. that same just with three.
a| What is the chance that all the children are girls.
The chapter here shows the equtations...
Another guy that wants to shout out his oppinion without reading all that's before him.
For me it is different in that I find much meaning, but I also feel small. I'm supporised when someone says they can't find meaning in anything for to me there is so much. Maybe if you can't find a meaning...
Or "Red at least once means 3 out of 4 outcomes. the 3 outcomes is defined by 'first spin is red', "third spin is not red", "fourth spin is red", and last as 'can be anything'" (Taking out my favorable/can-be-anything.
uh, something like that? Closer? Grr, I don't like getting math not to...
No, I was just kidding around when I said just the variables. I always hope I'm good at humour but I'm not.
My thought went as above(in case you haven't seen it):
we have two spins, divided by a +.
First shows the probability-of-one red and probability-of-can-be-everything(uh), the...
Because we have all the variables? Not enough?! Because..... we have two spins, divided by a +.
First shows the probability-of-one red and probability-of-can-be-everything(uh), the second of probability-of-one-red and probability-of-one-red. We have all the possibilities of...
I think I liked can-be-anything definition better.
hm, the 7/8 is a bit confusing to me. I'm abit visual and thinking 7/8 which is 'such a big number' is nothing falls unatural, but this is probably(whaha what a pun) quite normal.
Riight, I'll get some balls. hehehe.
No I mean.. directly translated it's favorable/those that might happen.
They are strange words to me. Uh. (Edit: Or it's like I see the math and don't see the math. Strange)
heh, pulling out balls from a bag was my previous test.
I'm having these sentences in my mind, but they fall out again fast.
I must specify... one red(R) x all(=NN)or:(8/8) , (I have these RN NN things a lot in my mind here, lol) ? hm...
AND you get the possble into it also. Are we sure this is probability and not magic? *laughs*
But shoudn't I as I think, putting it into that / ? So I get the 8/8 at the bottom as the possible
And also I'm maybe a little confused as to how you would get to the answer from the other way...
Well approximately it's right because you have all the 3 spins and the probable and possible. But.. ah yes, it doesn't matter of course that you muliply the 8/8 into it because anything muliplied by 1 doesn't change.
(1/8)(8/8) + (7/8)(1/8)
Why is the 1(8/8) at just one side?.. Because it doesn't have to be more of it? I'm a little confused at it's presentation. How do I transform it from that, to ((1/8) + (7/8)(1/8)(probable)) / (8/8/(possible))
But I'm thinking as above: " all is the possible and the rest is the probable(3). That would make perfect sense(?) uhm. It's as if you make a division into a sentence. O_o you'd have to multiply the 'no red x one red' with 'all' to make it a whole division "
Yeah. I've noticed homework does that :o :)
probability of one red x probability of ... lol. 7/8 is no red(all the other colours)?, but that makes 8/8...? ... a big nothing?:o yaaarwg No, all the colors? But that's neither R or N.
RNxNR:(R(at least one red))(N(no red))+(N(No red))(R(at least one red)) . But where's the RR and the other NR?
... (R(1/8))(N(8/8)+(N(7/8)x(R(1/8))... No..
or R(probablility of at least one red)N(probability of no red) + NR huh.
... Thinking :)
"N is no-red. R is red.", yes, this I get... something like it.
You mean a x between second-red and third-not-red right?
at least one red x no red + (but shouldn't it stand 2/8 here, that would give probabllity for at least two reds) x at least one red. gaaawd, I'm so confused.
lol. I don't get the 8/8. .. ah it's 'no red' of course... right? *hits my own head* Why didn't I think that way... I got to think math to language/pictures O_o?! I'm afraid of probability. Cause I'm much better at maths than language and probablity seems to me to be more language oriented(?)...
That gives two results. I'm leaving out the 3/4(Probable/Possible(sp?!)) of course, but I don't seem to make that add up: Like (1/8)x(8/8)+(7/8)(1/8) (a third spin here? But that would make over 15). And then add four divisions at the bottom(Possible results), but that would makes a lot of...
hm, maybe I see, I start at of at the wrong place? I started thinking off at P(a)xP(b).
But...um.. so.. RR((1/8)x(1/8)) x RN(1/8)x(7/8) x NR(7/8)x(1/8) doesn't work ?
But then I miss Probable/Possible(NN being here)
(Work. I'm thinking I should maybe do more of the easier ones first)