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1. ### What's your favorite movie?

The Talented Mr Ripley, Get Shorty, The Mission, 12 Angry Men, Howard's End.
2. ### Memorization for History Exam

Or you can use a strategy that has been put forward in a book here recently in Norway. A guy who's world top at memorizing cards use two techniques: travelroute and images. You use familiar places, like your home, and walk through each room. You'll recognize these rooms very well because it's...

Great :)
4. ### General Integral rules

yes, i am. Yeah, I figured. Like this right?: \int 5 x e^{x^2}dx = 5/2§2xe^(x^2) = 5/2§ (and as in opposite of the above e^(x^2)*2x) = (e^(x^2)) , which gives simply 5/2(e^(x^2))+C.
5. ### General Integral rules

so.. : testing.. \int 5x e^{x^2}dx = 5/2 \int 2x e^{x^2}dx = 5/2\times2\times \frac{1}{1+1}x^1+1
6. ### General Integral rules

no, it's rule 2? e^(x^2)= 1/x^2*e^(x^2), it would make the x^2 disappear anyway.. and would make sense at the least.
7. ### General Integral rules

(e^u)*u I'm making a fault here? no chain rule in integral? e^(x^2)=e^(x^2)? , but why isn't chain rule being used? (like in §e^(3x-2)dx=(1/3)e^(3x-2)+C.) it looks like it should, heh. And how do the x^2 dissapear..
8. ### General Integral rules

Where do I find LaTeX? Yeah, I meant chain rule. in is natural logarithm, e^inp=p. My try went: §5x*e^(x^2)dx= 5/2§2x*e^(x^2)dx (cause here is where you 'use it', right? = 5/2*2*(1/(1+1))x^(1+1)*(e^u)*u (chain rule) = 5/2*x^2*e^(x^2)*(1/(2+1))x^(2+1) = 5/2x^2*e^(x^2)*(1/3)x^3+C.
9. ### General Integral rules

oh no, sorry the answer is: (5/2)*e^(x^2)+C... (at work, brb)
10. ### General Integral rules

Homework Statement Solve (e^(x^2)) , use this result to solve §5x*e^(x^2)dx Homework Equations * is multiply  is derive 1.§e^xdx=e^x+C 2.§e^kxdx=1/k*e^kx+C 3.§a^xdx=1/ina*a^x+C (a is a number) 4.§k*f(x)dx=k*§f(x)dx The Attempt at a Solution (I'm alittle confused as to...
11. ### Probability with independent outcomes

uh, are you joking with me, or am I writing down the question wrong(cause I know I have a bad habit of not reading the question at probability well enough)? Cause that was the way I was thinking as you above.
12. ### Probability with independent outcomes

Yeah, b| the probability of that the eldest is a brother, and the two youngest girls. That is also just one outcomes yes? So that should give 1/8. But the answer writes as 0.121, which is not 1/8. ?
13. ### Probability with independent outcomes

Yeah, I guessed so too, but then I've thought so before too and being wrong, so.. *g* Hm, I'll ask about b| soon.
14. ### Probability with independent outcomes

Jeeserssweesers(for a lack of a better word), probability is confusing. Homework Statement A family has three children, no twins or.. that same just with three. a| What is the chance that all the children are girls. Homework Equations The chapter here shows the equtations...
15. ### What's the point of life

Another guy that wants to shout out his oppinion without reading all that's before him. For me it is different in that I find much meaning, but I also feel small. I'm supporised when someone says they can't find meaning in anything for to me there is so much. Maybe if you can't find a meaning...
16. ### Why do men weep

I cried to Jerry Springer when I was 16 or something when I was at my friends place, I couldn't watch it and had to leave, heh.
17. ### Independent Probability

Or "Red at least once means 3 out of 4 outcomes. the 3 outcomes is defined by 'first spin is red', "third spin is not red", "fourth spin is red", and last as 'can be anything'" (Taking out my favorable/can-be-anything. uh, something like that? Closer? Grr, I don't like getting math not to...
18. ### Independent Probability

No, I was just kidding around when I said just the variables. I always hope I'm good at humour but I'm not. My thought went as above(in case you haven't seen it): we have two spins, divided by a +. First shows the probability-of-one red and probability-of-can-be-everything(uh), the...
19. ### Independent Probability

Hm, because ...? I have to go to work. I'll take little look into it before I reply again! This is fun and helpful.
20. ### Independent Probability

Good question. Because we have all the variables? Not enough?! Because..... we have two spins, divided by a +. First shows the probability-of-one red and probability-of-can-be-everything(uh), the second of probability-of-one-red and probability-of-one-red. We have all the possibilities of...
21. ### Independent Probability

I think I liked can-be-anything definition better. hm, the 7/8 is a bit confusing to me. I'm abit visual and thinking 7/8 which is 'such a big number' is nothing falls unatural, but this is probably(whaha what a pun) quite normal.
22. ### Independent Probability

can be anything... wow. (Edit: Yeah well that is I suppose my "those that might happen") (7/8)(1/8) is first-spin-no-red x second-spin-one-red
23. ### Independent Probability

Riight, I'll get some balls. hehehe. No I mean.. directly translated it's favorable/those that might happen. They are strange words to me. Uh. (Edit: Or it's like I see the math and don't see the math. Strange)
24. ### Independent Probability

heh, pulling out balls from a bag was my previous test. I'm having these sentences in my mind, but they fall out again fast. I must specify... one red(R) x all(=NN)or:(8/8) , (I have these RN NN things a lot in my mind here, lol) ? hm...
25. ### Independent Probability

I'm not sure how you say in english, but here(norway) it's G/M(gunstige(all the probable(or wanted)/mulige(all the possible outcomes), and use it alot(?) through probability.
26. ### Independent Probability

AND you get the possble into it also. Are we sure this is probability and not magic? *laughs* But shoudn't I as I think, putting it into that / ? So I get the 8/8 at the bottom as the possible And also I'm maybe a little confused as to how you would get to the answer from the other way...
27. ### Independent Probability

Well approximately it's right because you have all the 3 spins and the probable and possible. But.. ah yes, it doesn't matter of course that you muliply the 8/8 into it because anything muliplied by 1 doesn't change.
28. ### Independent Probability

But that woulnd't make sense above cause then 8/8 is multiplied into both factors..
29. ### Independent Probability

(1/8)(8/8) + (7/8)(1/8) Why is the 1(8/8) at just one side?.. Because it doesn't have to be more of it? I'm a little confused at it's presentation. How do I transform it from that, to ((1/8) + (7/8)(1/8)(probable)) / (8/8/(possible))
30. ### Independent Probability

But I'm thinking as above: " all is the possible and the rest is the probable(3). That would make perfect sense(?) uhm. It's as if you make a division into a sentence. O_o you'd have to multiply the 'no red x one red' with 'all' to make it a whole division "
31. ### Independent Probability

It's one red x all colours. Why it's the right answer presents a difficulty :)
32. ### Independent Probability

So.. you'd have to multiply the 'no red x one red' with 'all' to make it a whole division(sp?) Why I'm really thinking this way I'm not totally sure.
33. ### Independent Probability

all is the possible? and the rest is the probable(3). That would make perfect sense(?) uhm. It's as if you make a division into a sentence. O_o
34. ### Independent Probability

oh. ah. Now I maybe see the / (?)
35. ### Independent Probability

one red x all + no red x one red.. O_o
36. ### Independent Probability

Yeah. I've noticed homework does that :o :) probability of one red x probability of ... lol. 7/8 is no red(all the other colours)?, but that makes 8/8...? ... a big nothing?:o yaaarwg No, all the colors? But that's neither R or N.
37. ### Independent Probability

It means 1 out of 8...
38. ### Independent Probability

heh. um.. 1/8 means 1 divided by 8, lol. ? But I was sure previous in my book that meant the probability of at least one colour. *really hungry, buys something to eat*
39. ### Independent Probability

(R(probability of at least one red)(1/8))(N(no red)(8/8))+(NN(?!)(7/8))x(R(probability of at least one red)(1/8))
40. ### Independent Probability

RNxNR:(R(at least one red))(N(no red))+(N(No red))(R(at least one red)) . But where's the RR and the other NR? ... (R(1/8))(N(8/8)+(N(7/8)x(R(1/8))... No.. or R(probablility of at least one red)N(probability of no red) + NR huh. ... Thinking :)
41. ### Independent Probability

checked. "N is no-red. R is red.", yes, this I get... something like it. You mean a x between second-red and third-not-red right? at least one red x no red + (but shouldn't it stand 2/8 here, that would give probabllity for at least two reds) x at least one red. gaaawd, I'm so confused.
42. ### Independent Probability

What's 7/8 ? (checking my books)
43. ### Independent Probability

No, where's the RR?
44. ### Independent Probability

lol. I don't get the 8/8. .. ah it's 'no red' of course... right? *hits my own head* Why didn't I think that way... I got to think math to language/pictures O_o?! I'm afraid of probability. Cause I'm much better at maths than language and probablity seems to me to be more language oriented(?)...
45. ### Independent Probability

That gives two results. I'm leaving out the 3/4(Probable/Possible(sp?!)) of course, but I don't seem to make that add up: Like (1/8)x(8/8)+(7/8)(1/8) (a third spin here? But that would make over 15). And then add four divisions at the bottom(Possible results), but that would makes a lot of...
46. ### Independent Probability

hehe sorry. I don't know where to begin maybe. Well I have a B from 1mx actually, but it is a bit too long ago. I'm having a hard time only with probablity . um, (1/8)x(8/8)+(7/8)(1/8) ?!.. no..
47. ### Independent Probability

7/8 + 8/8 ? O_o The.. 7/8 would stand for no red, the 8/8 for all red, but that wouldn't make sense.. 7/8 + 4/8 + 4/8.. no. Um.. arg, I don't get it.
48. ### Independent Probability

Ok, no I really meant multiplied. I'll be back. Thanks a lot for help. Yeah, thinking like that helps me sometimes.
49. ### Independent Probability

hm, maybe I see, I start at of at the wrong place? I started thinking off at P(a)xP(b). But...um.. so.. RR((1/8)x(1/8)) x RN(1/8)x(7/8) x NR(7/8)x(1/8) doesn't work ? But then I miss Probable/Possible(NN being here) (Work. I'm thinking I should maybe do more of the easier ones first)
50. ### Independent Probability

Ah, that gives four spins..! Yep, it's a mess in here :) I wrote down two answers that seemed the closest to what I felt would give the answer, eheh. Um, ah yes, that gives 3/4, yes?