That's one of my favorite problems.
I think the answer is about 24,000mi. Don't forget to subtract the radius of the earth. I always forget to do that!
Me and my fellow class mates were able to find 32 as well for a.
Nice work!
You're a janitor that does physics in his spare time? Are you like Will Hunting? :D
Yeah you got me there. I should specified identical particles.
So say all are electrons.
I ask because Prof. Webb specified "indistinguishable Fermions". So that would indicate were not talking about electrons and protons, in which case the Pauli Exclusion Principle doesn't apply, Protons...
Problem:
Consider a non-interacting system of 4 particles with each particle having single-particle states with energies equal to 0, e, 2e and 3e. Given that the total energy of the system is 6e, find the number of microstates of the system (and identify the microstates) if the particles are...
Yi(x,t) = A*Sin(kix - {&omega}it), where i = 1, 2, 3
Phase velocity for two wave can be given by v = (&omega + [&omega]')/(k + k') and group velocity u = (&Omega - &omega')/(k - k') but what about three waves?
I'm not sure what to do for three waves. I've looked all over my text and...
Navigation is one use off the top of my head.
Our calander is based on astronomical patterns (loosely).
Future uses. The cosmos is a place where we can conduct observational expirements to learn about physics that we can't replicate here on earth, black holes for example. Einstein's...
A surface current equal to Js is flowing on the surface of a perfect conductor in the x-z-plane traveling in the positive x direction. At a distance y = L along the y-axis lies the central axis of a cylindrical conductor with radius “a” and having a volumetric current distribution Jv= Jo*r*ex...
In my EM textbook it uses a equal sign with a triangle on top to define the intrinsic impedence of a lossless medium.
I think it means definition but I'm not certain.
The text is 2004 edition of author Ulaby titled Fundametals of Applied Electromagnetics, pg. 265.
Thanks
Nevermind I fiquered it out. Not sure why it's right, but I discovered how to find the correct answer using, a different system of matrices, the correct system. I didn't need to include a diffraction for the scratched surface (apparently). If someone could explain to me why not, I would be...
Here is the problem:
A glass sphere with a diameter of 5cm has a scratch on its surface. When the scratch is viewed through the glass from a position directly opposite, where is the virtual image of the scratch, and its magnification? The glass has an index of refraction n=1.50. Explain the...
N= [i,1;-1,i]
I used this theorem: N N-1 = In
Thus:
[i,1;-1,i]*[a,b:c,d]=[1,1;1,1]
I then found:
ia+c=1
ib+d=1
-a+ic=1
-b+id=1
Can I conclude an inverse does not exist. If so, how?
If not, what do I do?
Thanks,
Frank
The a in your equation (the acceleration of gravity at the Earth's surface) should be negative, if you want the direction down towards the center of the Earth to be negative. This should fix the sign to be vo = 9.8 m/s.
Note: When doing problems draw a picture and label it with a frame, i.e...
I actually trired that method, but was unsure if it was correct since the terms were so messy. I'll continue with that method and post my solution.
Thanks.
The problem states:
Express Cos( Θ1 + Θ2 + Θ3) in terms of Sin(Θk) and Cos(Θk), k = 1, 2, 3, using the relation e+/-i*Θ = Cos(Θ) +/- i*Sin(Θ). [Hint: Use the product property of the exponential e.g., e(Θ1 + Θ2) =...
Interesting idea. I imagine the only thing you could do with the heat is heat water. Some how incorporate that heated water into a system with the water heater. Surprisingly that sounds like a practical idea, could save quite a bit of energy over a few months of use during the summer. But if...
I was bored earlier today, so I concluded the best way to elevate my boredom was to exercise my brain for next quarter. The best way to exercise your brain is to do a little physics, right?
I started to think of a problem. I came up with a classic projectile problem: A cannon fires a...
I'll have to think about it further...
Why does the B-field need to change in the z direction to impart a deflection on the Ag atoms? I haven't quite grasped that concept, maybe my B-field knowledge is a little rusty?
If Fz changes according to &muzdB/dz and the silver atoms are collimated into a beam how does the dipole magnetic moment of the atoms see and change in the B-field if the beam is cutting across the B-field perpendicularly?
How does a changing B-field, in the verticle direction affect the Ag...
I get:
t = 1.62 x 1012s
Is this correct?
Thanks
Edit:
Which is 51374 years.
I just looked up how old C-14 dating is good too. It said 50,000 years. So it looks like I'm right.
This problem was easy, I don't know why I struggled with it so much!
Libby's observation that all the carbon in the world's living cycle is kept uniformly radioactive through the production of C-14 by cosmic radiation led to his development of the radioactive carbon dating method. Samples of carbon in the life cycle have been found to have a disintegration rate...
I like your way much better.
I ended up with a &gamma2/[(&gamma +1)(&gamma-1)] = 4/9mc2, solving for v would have been fun. I bet I made some mistakes along the way, two pages of algebra and I write small. Plus that I tried to solve for K directly, then subsituted that and tried to go for v...
Is this okay?
Ephoton + moc2= 3moc2 + 3Ke
Ephoton = energy of the photon: hc/&lambda
moc2 = rest mass energy of electron
Ke = kinetic energy of the electrons in motion (all three with equal linear momentum and kinetic energy) after the photon collides with the initially motionless electron.
Problem:
A photon of energy E strikes an electron at rest and undergoes pair production, producing a positron and another electron.
photon + e- --------> e+ + e- + e-
The two electrons and the positron move off with identical linear momentum in the direction of the initial photon. All...
I worked out all of the kinks. I was wrong.
I found:
1 = L/&pi A2[1/2&pi]
The integral was more challenging than I thought.
Thanks for your help.
I would of never thought of the u substitution, I haven't done that sort of thing since Calculus II.
You're not understading:
Let me give you all my work to alleaviate any confusion.
Show that A = (2/L)1/2
&psi(x) = A Sin(&pi x/L)
&psi2(x) = A2 Sin2(&pi x/L)
[inte]0L &psi2dx = 1
A2[inte]0L Sin2(&pi x/L) dx = 1
Actually...
I forgot to resubsitute...
BTW: I only use a...
Here is the problem:
A diatomic gas molecule consists of two atoms of mass m separated by a fixed distance d rotating about an axis as shown. Assuming that its angular momentum is quantized just as in the Bohr atom, determine a) the quantized angular speed, b) the quantized rotational energy...
HAHHAHA!
That's what happens when you do physics for 10 hours straight.
Edit: BTW, I've never seen that type of unit used before so my brain must have dismissed it.:smile:
For the ground state of the hydrogen atom, evaluate the probabilty density psi^2(r) and the radial probability density of P(r) for the positions.
a) r = 0
b) r = rb
I confused how this probability function is used. What's the technique here?
Thanks
Calculate the smallest allowed energy of an electron were trapped inside an atomic nucleus of diameter 1.4x10^-14 meters. Compare this number with the several MeV of energy binding protons and neutrons inside the nucleus. On this basis, should we expect to find electrons within the nucleus...