@quarkyphysicsgirl What is the context of this problem? Is it from an introductory physics course? When they say "long solenoid" it is supposed to be an indication that the formula for ideal solenoid is used. The point indicated (4.54 cm) it is outside the solenoid (radius is 2.08 cm) and the...
The amplitude is not time dependent. It should be a fixed value for a given position, x.
Everything that multiplies the time dependent term is the amplitude.
Why dismiss the matter of fact part? If magnetism were not a fact nobody would have bothered to try to make a model of it. There would had been to "it" to start with.
Actually, both pairs are technically called "components". The ones obtained by projection on the two axes are the contarvariant components and the other ones are the covariant components of the vector. Only for orthogonal axes they are the same. But we are so used to the orthogonal case that is...
First, there is no "delta W". The work (not change in work) is equal to the change in kinetic energy. This is because the work is a quantity that describes what happens in a process, in the transition from initital to final state. The kinetic energy, on the other hand, is a quantity that...
"Equilateral" means all sides are the same size (equal sides). You don't need to split it and to form right angle triangles. You seem to have a tendency to pick the most complicated ways to solve things., 😃
That angle is 60 degrees but the extension of the black line is not along the dotted line that you show in the previous drawing. You see here that the black line is not at 90 degrees relative to this dotted orange line.
No, there is not. What is that dotted orange line? If you draw it perpendicular ot the direction of ##\Delta \vec{r} ## then the other angle is not 60 degrees. But you don't need that dotted line. Just draw the weight where ##\Delta \vec{r} ## starts.
The potential difference between two points a few centimeters apart on a cable with very low resistance is very small. Typical currents in high voltage power lines are given as few thousand amperes (I found 4000 A value quoted for the very high voltage lines) to few hundred amps in the secondary...
Yes, the plate and the boundary conditions. You can easily find the vibration modes calculated for plates with free edge, clamped edge or "simply supported". By "easily find" I mean in books or papers. To calculate them is quite a job.
They have different patterns and different frequencies even...
"Conserved" means same value before and after a process (or just a at two different times). It applies to state parameters like energy, momentum, angular momentum. Work is a process parameter and "conservation" does not apply to it. You don't have a work before the collision and another after...
The resonant frequencies are specific to the plates and do not depend on the frequency of the driver. They are the frequencies corresponding to the normal modes of vibrations.
The plate vibrates with the frequency of the driver, as any forced oscillation. As you change the frequency of the...
The resonant frequencies will be different. The shapes may or not be different. You see the shapes when the frequency of the vibrating device is close to one of the resonant frequencies of the plate. You may see the same shape (or similar) on different plates, but at different frequencies. The...
Won't be easier to just find the moment of inertia for a square of side L and mass m and then use the results for any value of L and for any way this side is related to another parameter in the problem, like to the radius here? You can do this in two or three lines, even by using the integral...
If you have both types of carriers they have different drift velocities (different mobilities) so the Hall voltages don't cancel out even if they have the same concentration. In doped semiconductors they have both different concentrations and different mobilities
You can do this without extra integrals. You can calculate the moment of inertia of one of the sides around the center by using the parallel axis theorem. You know the moment of inrtia about an axis going through the middle of the side. ##I=\frac{1}{12}ma^2## where m is the mass of one of the...
You know that this is related to some chapter in a book where a specific type of wave is described. Possibly just a plane wave in 1 dimension. But this is not the only wave possible and a linear dispalcement (position of particle) is not the only parameter used to describe a wave. What you know...
I am trying to find this description in astrophysics textbooks but did not find it so far. Do you have a reference to textbook on stellar interior describing this bouncing of photons through the solar/stellar interior?
My original post was based on the suspicion that this is just a pop science...
Then why propagate this image of a photon bouncing like a pinball ball towards the surface and eventually escaping into space?
Not all the processes contributing to the opacity of the solar interior are ellastic scattering where you may argue that is the same photon but with the lower energy...
Then this is already labeled as Q total. This is the charge on the upper group of capacitors. And the same charge is on the lower group, which is in series with the upper group.
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The energy carried by the initial gamma photons reaches the surface after a long time. But the photons themselves? How do you tell that the visible photons are the same as the initial gamma photons? Are the two photons involved in Compton scattering, for example, the "same" photon or are they...
The field can be discontinous. And actually is across any surface charge distribution. Of course, a really 2D charge distribution does not exist in reality but the disconinuity is a well accepted fact in EM books and the change is even expressed as a function of the charge density. The potential...
The light emitted by the star's surface is made of photons who did no bouncing inside the star. The gamma photons emitted by the thermonuclear reactions don't reach the surface. Even if they did, we won't see them.