Yea i just realized that thanks..so it would be 15+(-5) = 10 N
But weight isn't only the mass, from what i know weight is equivalent to net force that's why it's measured in Newtons..that's where I'm getting confused!
oh btw the answer at the back of the textbook says d) 5m/s^2
Hey guys, I reallly don't understand how to do this question. i'd really appreciate it if you can help me..thanks :)
A person applies a force of 15 N [E] on an object of weight 20 N. If the force of friction has a magnitude of 5.0 N, what is the acceleration of the...
Yes, I was thinking about that but how do I do it? Seeing as if i did m=di/do 4=di/do --but it leads me to a dead end
or if i used 1/di+1/do=1/f i can only go as far as 1/di+1/do=1/20 then once again i get to a dead end!
A lens has a focal length of 20 cm and a magnification of 4. How far apart are the object and the image?
1/di + 1/do = 1/f
The Attempt at a Solution
Well, I don't really know what to do, I feel like I don't have enough...
A block of mass m1=2.0 kg on a frictionless inclined plane of angle 20 degrees is connected by a rope over a pulley to another block of mass m2=1.0kg. What are the magnitude and direction of the acceleration of the second block?
so i basically cross-multiplied and got 35(x+50) = 40x
which then gave me 35x + 1750 = 40x
sub x=350 into x/35
350/35 = 10s
That doesn't make sense because the final time is supposed to be 5:40 (basically 40 minutes to add onto 5:00)
Hello! I have another question ..sorry!
Mr. Jones lives 50 km away from you. You both leave home at 5:00 and drive toward the highway. Mr.Jones travels at 35km/h and you drive at 40km/h. At what time will you pass Mr.Jones?
From the book the answer says: 5:40
This is what...
An object is dropped from a tower. If it had been thrown down at 60m/s, it would have taken half the time. What is the height of the tower? (acceleration is 10m/s^ down)
d= v1(t)+1/2a(t)^ ----> I think you could use this
a=v2-v1/t --> maybe...
okay thanks. One more question.. well actually 2.. if someone knows how to solve problem 2 i would really appreciate knowing how!
Average velocity is taken care of now but average speed you you subtract d2-d1 or add d1+d2? Same would go for time...
So the average speed is going to be 2750 + 5810/ 27+ 65 which is 93m/s ??
The average velocity would be -2750 + (-5810) / 27+ 65 which is 93m/s (SW)
Is it right that i added the signs for the velocity?
A plane flies 2750 m[W] in 25s and then 5810m [S] in 67s
a) What is the average speed of the plane?
b) What is the average velocity of the plane?
I tried doing it and I don't know if I'm right. My physics teacher can't explain anything for beans so could you please explain...