No, I'm just using this as a tex notepad since no one was helping when I needed it. I'm good with all these.
v = \lambda f
\lambda = 4L
v = 4L f
f = \frac{v}{4L}
iii) (challenging) now consider a wave made from a superposition of modes:
\sum_{n=1}^{\infty} a_n\cos(\omega_n t)\sin(\frac{2\pi n}{L} x)
calculate the total energy of this wave and comment on your answer.
I get the KE and PE each to be 0 by the expression in post 3. We have...
The differential equation modelling this system is given by:
m\Ddot{x} + 2\beta \dot{x} + \omega^2 x = 0
With \beta \ and \ \omega defined as
\beta = \frac{b}{2m} \ and \ \omega = \sqrt{\frac{k}{m}}
with m being mass, k the characteristic constant of the physical system, and b...
Using Newton's 2nd Law for a damped oscillator:
ma = -kx - \alpha x
which is a second order linear DE. To solve it we use the trial integrating factor e^{\lambda x} [/tex] to come to the root equation
mx^2 + \alpha x + k = 0 where we can find our two solutions to be
r_{1} \ and...
She was pretty upset about that. It's not that bad out.
Trib, tonight was your night but you lost it haha. We went to the drive in and almost watched a couple movies. Feel free to take us all out to dinner though o:)
Smurf, pretty sure your hand doesn't have an STD. Both hands..
Shes in a hotel for the week, its working out pretty well.. and I say that in the least suggestive way possible. I'm on my way down there in a bit but don't think I'll be able to keep her company all day. We'll see. Any messages for her?
It's a hookah bar/arabic restaraunt. She posted that at about 11:45 so it's not so late, the place is open til about 2ish but most restaurants are open til about midnight or so, unless its really chic.
Maybe incompetent wasn't the word but, sometimes I feel that this course of study requires an intellect and skill above that which I have. Granted, and I dn't mean to be full of myself, I'm a pretty smart kid, I still think the bar is still a little higher in terms of 'natural ability' than I...
It is tangent to the surface at that point and I think that is what he is meaning, but when youre dotting D_{\theta}f(x,y) why did we get a negative cosine?
You also forgot your j unit vector in the first expression.
Then you would say that the total force is the electric force (F=qE) and follow Newtons second law (F=ma) and combining the two you can find the acceleration (while in the field).
Youre right. When you take a directional derivative what kind of product do you use (for the two vectors). One of these two is at a maximum when the angle is zero, that's the one you want to use.
If you're still stuck, show the defining expression for a directional derivative.
Conservation of momentum theory says that the net momentum stays constant if there are no external forces acting. Are there any external forces? What was the initial momentum?
Find the CoM in each direction seperately. Meaning stack all the blocks so that you only have one direction to deal with at a time. For example, imagine a figure with 3m on the left column, 2m in the middle column, and 1m on the right column (where m is the mass of one block). then find the...
d is the displacement against the force of gravity. Gravity acts in the vertical direction.
I recommend you actually learn what the letters really mean instead of just plugging things into formulas.
The position vector points from the origin to the position of the particle. For your point it is < x , y , z >
Positions that vary with time are expressed as functions of x y and z, and you get parametric functions:
\vec{r}_t = < x(t) , y(t), z(t) >
abby, wake up. you're dreaming again. keep talkin that much **** and you'll be the one needing biochemical supplements after trib and i are done with you.
Yeah you could get a crowd. It would be an upset for you though, unfortunately for you its the underdog that wins these kind of things. You live by Main Street Billiards?