omg, I am so dumb... i totally didnt think of it that way... Thanks.
I started to look at it as charge and stuff, and I kinda thought i figured it out, but man...
Thanks a lot.
well, as I understand it:
Once C1 and C2 are fully charged no current flows through the two branches because the capacitors act as an open circuit. So that would mean that the current through the reisitors is 0 and therefore no voltage drop.
However, because the two capacitors are now...
its been a while since i did ne java, but if u just put:
public void actionPerformed(ActionEvent evt)
{
getInput();
calculateShipping();
displayOutput();
}
Just adding it before u call displayOutput should calculate the shipping, then u can...
[SOLVED] RC Circuit Help
Homework Statement
What is the potential of point a with respect to point b in the circuit shown when switch S is open? Which point, a or b is at a higher potential? b.) What is the potential (after a long time) of point a with respect to ground when switch S is...