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Need help calculating Shear on a 5/8" square key PF, I am trying to figure out how to calculate the shear on a 5/8" x 5/8" x 3-1/2"L standard shaft key, when the OD of the shaft it fits into is 3". A tire of ~40" dia rides on the shaft and at any given time, let's say a load of 20,000lbs is...

Bob, your explanation more closely correlates to what I seeing in the field wrt 2 - 3 HP motors moving heavy loads; after reading your post, I researched a little more to see where the Cf I've been using is much to large and none applicable in this case since it is a rolling friction and not...

Yes, I am using an equation found on pp. 277 of the 25th editiong Machinery's Handbook which I thought was appropriate.

Thank you jack action. The force required to get that size of a load moving is a concern for me; I am still working on this and have decided to increase the size of the electric motor from 3 to 5 HP (1750 RPM, 15.4-14.2/7.1 AMPS) as well as the shaft diameter. While reading through my...

See attached sketch which represents total load of 40,000 lbs, including the parts and cart itself.

At this point, I've got the following: Full Load Torque, T=5252 x 2.5 HP / 15.27 rpm = 859.85 lb-ft This calculated torque creates a driving force of [859.85 lb-ft / (7.5/12) =] 1375.77 lbs of force at the wheels (real-wheel driven when cart fully loaded). If I select a 3 HP electric...

PF, I need to design a cart that will move (horizontally/linearly) a load of ~40,000 lbs including its own weight (about 6500 lbs) at a total distance of 70 ft on a set of rails. Known data: 1. Cart will need to move at a distance of 1 ft/s 2. Diameter of the cart wheels (4) is 15 in...