Well, resistance of equivalent resistor would be R_eq=2461.44 ohms.
KVL loop looks: +voltage of battery-(current*equivalent resistor)=0 => 12volts-current*2461.44ohms=0 => current=0.004875ampers
So what should I do next?
Homework Statement
Set voltage between 1. a-b; 2- b-c; 3 c-d 4. a-c; if voltage of battery is 12V and R_1=2000 ohms R_2=3000 ohms; R_3= 4000 ohms. (see attached file)
Homework Equations
voltage=final voltage- innitial voltage
resistors in series R_1,2=R_1+R_2
parallel resistors...