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  1. C

    Wheatstone bridge

    OK, thanks a lot.
  2. C

    Wheatstone bridge

    Ok, so now I choose 5 equations with 5 unknown currents, find them and using Ohm´s law I will find voltage on resistors?
  3. C

    Wheatstone bridge

    There should be two loops involving source: ε-R_1*I_3-R_2*I_5=0 ε-R_2*I_1-R_1*I_4=0
  4. C

    Wheatstone bridge

    You mean: -I_3*R_1-I_2*R_3+I_1*R_2=0 -I_2*R_3-I_4*R_1+I_5*R_2=0 I_1+I_2=I_4 I_3=I_2+I_5 ?
  5. C

    Wheatstone bridge

    Well, resistance of equivalent resistor would be R_eq=2461.44 ohms. KVL loop looks: +voltage of battery-(current*equivalent resistor)=0 => 12volts-current*2461.44ohms=0 => current=0.004875ampers So what should I do next?
  6. C

    Wheatstone bridge

    Homework Statement Set voltage between 1. a-b; 2- b-c; 3 c-d 4. a-c; if voltage of battery is 12V and R_1=2000 ohms R_2=3000 ohms; R_3= 4000 ohms. (see attached file) Homework Equations voltage=final voltage- innitial voltage resistors in series R_1,2=R_1+R_2 parallel resistors...
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