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  • Users: joejo
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  1. J

    Easy half life question

    FINALLY! YAY thanks alot! :)
  2. J

    Easy half life question

    or is it 24000 years now... because 6000*4
  3. J

    Easy half life question

    4 half lives...is the rest right?
  4. J

    Easy half life question

    1) 16 half lives... 2) 6000 years 3)96 000 years.. is that right
  5. J

    Easy half life question

    my test is in a few hours...if your planning on helping me out stop confusing me...you could help by telling me what the answer. thanks
  6. J

    Easy half life question

    therefore the answer to c) is 375 years.
  7. J

    Easy half life question

    375 years...my test is in 5 hours...can someone please just check my answer and if its wrong state the correct answer...i've been up all night...thanks
  8. J

    Easy half life question

    thanks hall of ivy...as for that below... there are 4 half lives...making it 8 years correct? The piece of wood starts with 32 g and eventually has only 2 g. It has 2/32= 1/16= (1/2)4 as much as originally. That means 32 is multiplied by 1/2 4 times. How many half-lives is that...
  9. J

    Easy half life question

    the number of half lives...my test is 2mr...can someone please answer it...its almost 2am and i don't get half life questions
  10. J

    Easy half life question

    hallsofIvy you never seem to help people out... anyways...n is the number of half-lives it has had...is that right Doc G or anyone else that is willing to help...
  11. J

    Easy half life question

    is that it? 32(\frac{1}{2})^{\frac{n}{6000}}
  12. J

    Easy half life question

    so what would the equation be?
  13. J

    Easy half life question

    still lost...i don't get it...im trying to do this correspondance and its very difficult
  14. J

    Easy half life question

    im lost...can someone show me how to do it...i need to study of this now...
  15. J

    Easy half life question

    we haven't done logs...this is suppose to be a remedial math...I'm looking for someone to answer it properly so I use this question to study from...Can someone please help me out...
  16. J

    Easy half life question

    hey can someone help me out with this question...I have an test 2mr on this time and don't have any more time to waste. So can someone please show me how to do it...so I can study of it...thanks in advance Scientist are able to determine the age of very old, naturally occurring items...
  17. J

    Quick math question

    thanks guys...you all helped out a bit...Damincs answer was the way we did it in the book...Thanks Daminc!
  18. J

    Quick math question

    i haven't done logs yet...this is suppose to be grade 11 math...
  19. J

    Quick math question

    Thx faruk but wats ln?
  20. J

    Quick math question

    we haven't done that yet..any other way...
  21. J

    Quick math question

    Hi guys...can someone help me out with this problem... The population of Newfoundland and Labrador was 533,800 in 2001. At that time the population of Newfoundland was decreasing at a rate of 0.6% per year. The population of PEI was 138,500 in 2001. At that time the population was increasing...
  22. J

    Is this right? chem heat of combustion

    thank you...just to verify...my second answer (-891.1 kJ.) right?? sorry I am getting confused and I can imagine you are too! thanks again
  23. J

    Is this right? chem heat of combustion

    i wasn't being sarcastic...sorry for the misunderstanding...so was my second answer right...
  24. J

    Is this right? chem heat of combustion

    the bob...read above...i'll post it below just in case u never saw it. By definition the burning of methane to make CO2 and H2O is... CH4 + 2 O2 --> CO2 + 2 H2O The heat for this reaction is 2(-286.3) + (-393.3) -(-74.8) - 0 = -891.1 kJ. right??
  25. J

    Name these substances

    1) [CU(CN)3]2- =tricyanocuprate (I) 2) [Ni(H2O)6]2+ =hexaaquanickel (II) is that right?
  26. J

    Is this right? chem heat of combustion

    can anyone help me out?
  27. J

    Is this right? chem

    isn't that right...my first time with latex!
  28. J

    Is this right? chem

    K_c=\frac{[H_2O][CO]}{[CO_2][H_2]} \frac{(0.3)^2}{(1.7)^2} = 0.03
  29. J

    Is this right? chem

    Kc=[H2O][CO] over [CO2][H2] = (0.3)^2 over (1.7)^2 = 0.03?? am i right or wrong?
  30. J

    Is this right? chem heat of combustion

    By definition the burning of methane to make CO2 and H2O is... CH4 + 2 O2 --> CO2 + 2 H2O The heat for this reaction is 2(-286.3) + (-393.3) -(-74.8) - 0 = -891.1 kJ. right??
  31. J

    Is this right? chem

    shouldn't the answer be 0.03
  32. J

    Is this right? chem heat of combustion

    i think its still wrong... shouldn't it be... -802.3kJ
  33. J

    Is this right? chem

    lol thanks saltydog...i suck at latex...
  34. J

    Chem question curious?

    no i dont...
  35. J

    Is this right? chem

    can anyone help me out please?
  36. J

    Is this right? chem heat of combustion

    can anyone help me out?
  37. J

    Chem question curious?

    I don't have my textbook anymore...thats why I am asking up here..I finished school and handed in my textbook..this was a question of my grade 12 chemistry exam...i'm just curious...could someone please help me out...
  38. J

    Chem question curious?

    sorry there are soo many answers and you guys are losing me...can someone summarize the correct answer please...thanks again
  39. J

    Is this right? chem heat of combustion

    Hi guys can you please check if this is right...thanks in advance The heat released by the reaction 2C + 2H2 = CH4 is 74.8kJ/mol. Using this information and a table of standard enthalpy of formation values, determine the heat of combustion for the burning of methane to form CO2 and H2O(g)...
  40. J

    Is this right? chem

    Hi guys can you please check if this is right...thanks in advance Given the reaction CO2(g) + H2(g) = H2O(g) + CO(g). If initially there are 2.0 moles of CO2 (g) and 2.0 moles of H2(g) introduced into an empty 1.0L container, at 1800ºC, it is found that at equilibrium there are 0.3 moles of...
  41. J

    Chem question curious?

    im so lost...i don't know wat the answer was...now I am scared to see my mark...can someone please explain this to me...
  42. J

    Chem question curious?

    anyone else that is more confident
  43. J

    Chem question curious?

    well i don't know...it was on my exam that i just had today..and i didnt know how to answer it...thats why I am soo curious... can anyone please help me out..
  44. J

    Chem question curious?

    chem question...curious?! hi guys i was just wondering that if a solution of a weak acid has a salt of the same acid added to it, what would happen to the pH?? can anyone help me out...thanks in advance
  45. J

    2 quick chem question

    neone else?
  46. J

    2 quick chem question

    thx that clears things up a bit...As for increasing the rate of chemical reaction are there any more ways or just those...
  47. J

    2 quick chem question

    Why do geometric isomers only exist in the alkene family but not in alkanes? What are different ways of increasing the rate of a chemical reaction?
  48. J

    Altitude Question .

    yup...why is there something wrong with using the sine law
  49. J

    Altitude Question .

    thanks bob
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