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hm... becuase I have a spacetime diagram modeling this answer and it seems that it is only supposed to be 12 seconds...

btw, this is all from signal sender's frame of reference.

the ship is moving in the positive direct and is at 0 ls when t = 0

use styrofoam (or something equally light), stick a fan on the back. Add wheels. Voila.

a fan?

Homework Statement A signal (traveling at the speed of light) is sent from -4 ls (light seconds) towards a moving spaceship traveling at 0.866c. How long does it take for the signal to reach the ship? Homework Equations I'm pretty sure its t=(delta)D/c-v But I continue to get the...

but I'm not given the train's acceleration... am I missing something here =/?

Homework Statement A passennger is standing without slipping in a forward accelerating train. The coeffeciant of the feet and the floor is 0.47. Determine the maximum required acceleration of the train relative to the track if the passenger is not to slip Homework Equations F=ma The...

omg, how did I miss that 0_0 thank you, everything is 100% clear now =P

isn't the equation (mu)mg? mu = F/N right? So therefore F=(mu)N -> F = (mu)mg?

Solved, thanks guys

thats the thing though... it doesn't give you the mass. It ONLY gives you the force of kinetic friction and the initial speed

Homework Statement A skier on a slope inclined at 4.7 degrees from the horizontal starts down the slope with an initial speed of 2.7m/s. The coefficient of friction is 0.11. Determine how far the skier will slide before coming to a rest. Homework Equations Fnet=ma F(f) = (mu)N The...

Basically: givens v(1) = 0m/s F(t) = 21N (31 degree) (mu kinetic) = 0.5 (mu static) = 0.55 a = 0m/s^2 X component Fnet=ma F(t) - F(f) = ma F(t) = (mu)Mg m = F(t) / (mu)g m= 18N / 0.55*9.8 m = 3.3kg Y Component F(net) = ma F(t) = Fg F(t) = m/g m = 21Sin31 / 9.8 m =...

A boy is pulling on a box at a 31 degree angle using 21N of force. The box remains stationary. The co-efficient of static friction is 0.55. What is the minimum mass? When I use the component method to solve this problem, do I need to calculate the mass for both the Horizontal and the Vertical...

thank you so much

lol, so to sum it up: force exerted on ball = force exerted on racquet. However, ball flies away extremely quickly and racquet doesn't is becaue racquet is heavier and therefore according to Newton's second low, it doesn't accelerate as much (and also since the racquet is anchored to the...

yea, the equal and opposite force excerted on the racquet stated by the 3rd law.

F(a) = applied force F(n) = Normal force umm, yea sry. I was typing a bit too quickly. Third and Second law. nono, i mean if a tennis racquet was to hit a tennis ball. Would the applied force and normal force be equal or would applied force be larger?

Homework Statement for an FDB of an tennis ball hitting the racquet. Is the F(a)=F(n) or is F(a) larger then F(n). The Attempt at a Solution I think that F(a) = F(n). According to Newton's second law, they both receive the same force, however since the tennis ball has less mass...

Lol, thank you soooo much (again!)

Homework Statement An exceptional vertical jump from rest would raise a person 0.80m off the ground. To do this, what constant force would a 70kg person have to exert against the ground? Assume the person lowers himself 0.20m prior to jumping and remains in a standing position while in the...

ahh, ic. Thank you montoyas and Dr. Jekyll. I understand it now.

we haven't learned that yet... is it possible to only solve this problem with F=ma and the kinematic equations

[SOLVED] A falling man Homework Statement a 90kg man falls (freefalls) 10m, when he lands, his legs buckle and he goes down another 23cm. What was the average force he exerted on the ground? Homework Equations M = 90k a = 9.8 m/s^2 The Attempt at a Solution from freefall to...

ahh, ic thank you very much. That might explain why i never got anything by searching up alpha on google :P can you please tell me what it is called?

so would i derive a vs F or a vs m in the same fashion as: a (alpha) x a (alpha) y a (alpha) z a = xyz

I knew i should have paid more attention in class =/ anyways, We have been studying Newton's second law. And I have a question on my lab that asks for me to "derive equation for a (acceleration) vs F (force) and a (acceleration) vs m (mass)" a vs F and a vs M are two graphs which we did...