# Search results

1. ### Mesh analysis, one source?

solved it using the matrix, cheers lads xxx
2. ### Mesh analysis, one source?

ignore that last one I am going to try a different method haha

4. ### Mesh analysis, one source?

brilliant, thank you very much tiny-tom and matlabdude. ill let you know how i get on
5. ### Mesh analysis, one source?

just a quick on now, if i have mesh 1: V=R1*(I1-I2)+R4*(I1-I3) mesh 2: 0=R5*(I2-I3)+R1*(I2-I1)+R5*I2 mesh 3: 0=R3*I3+R4*(I3-I1)+R5(I3-I2) rearranged so they can be solved using a matrix will they look like this? mesh 1: I1*(R1+R4)-I2*(R1)-I3*(R4)=V mesh 2: -I1*(R1)+I2*(R1+R2+R5)-I3*(R5)=0 mesh...
6. ### Mesh analysis, one source?

bollocksed the calculation of R1, so here's the new picture haha
7. ### Mesh analysis, one source?

so it is this? I1= V=R1*(I1-I2)+R4*(I1-I3) I2= 0=R5*(I2-I3)+R1*(I2-I1)+R5*I2 I3= 0=R3*I3+R4*(I3-I1)+R5(I3-I2)
8. ### Mesh analysis, one source?

this question is part of my electronics CW, I've done it before, but briefly. and looking back at all my old notes I've realized that every single one I've done before has 2 sources and only 2 loops, whereas you can see from the image below that this has 3 and its getting me in quite a...
9. ### Furnace Heat transfer question

right cheers for that then. i know how to do it providing that is is delta 40, i also know how to do it given 2 temperatures so cheers for the help. was annoying me greatly much appreciated, ash
10. ### Furnace Heat transfer question

i was talking to my dad about it earlier today too. but that's the exact question, haven't re worded it at all. a furnace implies very hot temperatures, and the 40k must have to be a difference. but i wanted to see if i was overlooking something so posted on here. is there anyway to get any...
11. ### Furnace Heat transfer question

Homework Statement a furnace wall has an area of 3m^2. a thickness of 250mm and a thermal conductivity of 1.5 W m^-1 K^-1. calculate the rate of heat transfer through it when the temperature is 40K Homework Equations Q/t=KxAx(T2-T1)/L The Attempt at a Solution This isn't homework as such...