Search results

thanks for all the help!

thanks for the quick response! but, we haven't learned that in class... can you explain to me how \nabla \ works? how would I use it to solve the problem?

Hi, I have a problem with finding charge distribution. If anyone could provide help or any tips as to how to solve it, I would greatly appreciate it. I have already solved half of the problem. The potential V(r) of a spherically symmetric charge distribution is given by V(r) =...

ah! nevermind. i got it! first i had to find the electric field inside and integrate it, since dV=-E ds I just integrate it from the interval [R,r] and that gives me the answer! Thanks for all the help!

okay so the Electric Field inside is = (Q/4*PI*e0)(r/R^3). to find Potential, what would i do? After i find this potential, i add it to the potential outside to get the total? Thanks for all the input guys!

Hi, Could somebody please help me on a problem regarding Potential? Calculate the potential inside and outside a sphere of radius R and charge Q,in which the charge is distributed uniformly throughout. [Hine: The additive constant for the potential inside the charged sphere must be chose...

Thanks! I get it now.

So taking E = Q*x/(e0*4*Pi*R^3), I substitute that into E = F/q? Therefore, F = Eq = Q*q*r/(e0*4*Pi*R^3) Using F how would I obtain the total energy of the point charge? Period of motion? Wouldn't the total energy be PE + KE? I'm really not that good at Physics, can you explain the...

Thanks mukundpa! You were right...the E(rod) is equal to (lamda)/[2(pi)(Epsilon)r] I plugged in all the coefficients and it worked perfectly =) Can anyone help me with the second problem?

Hey everyone, I have two problems that deal with Gauss's law. The first one deals with Electric Fields. Charge is distributed on a long, straight rod with uniform density 6.5 x 10^-8 C/m. Compare the magnitude of the field 1 cm from the rod to the field 1 cm from a point charge q = 6.5 x...

thank you :) i really appreciate the help!

Thanks for the replies! Should I use F=kq1q2/r^2? then plug it into F=ma? or should I find E=kq/r^2 and plug it into F=qE? Sorry if these are very simplistic questions...Physics is hard for me =/

An alpha particle approaches a gold atom head on, stops, and turns around at a distance of 10^-11m from the nucleus. What is the electric field due to the gold nucleus at this point? Ignore the effects of the gold atom's orbiting electrons. What is the acceleration of the alpha particle when it...

thank you so much!

oops..i didnt realize the typo in the first post. i changed it. am i supposed to use F=kq1q2/r^2?

the book just says x=10, as in on the x-axis. it doesn't give specific units... the answer is 44.4 (no units) so that means that it's 4.44 times farther from -5q than +3q to -5q (10 units)

I typed it exactly as it is in the book. It really has me confused. The third charge is not given. So far it is -5q, +3q, and ?q. The net force on the charge is zero. Is there any way to figure out the third charge so that the net force would be zero? I'm thinking that if I find the...

Hi, I'm new here and I was wondering if anyone can help me with a physics problem regarding charge. Any input would be greatly appreciated! A charge -5q is placed at x=0 and a charge +3q is placed at x=10. Where on the x-axis is the net force on a charge Q zero? The answer is x=44.4...