Homework Statement
See picture please
Homework Equations
The Attempt at a Solution
Here is what I understand:
vi sin(theta) = initial velocity height on velocity/time graph
What I don't understand:
sqrt(gd/2) is this gravity times initial distance height of target?
Where is the second...
Thanks for the response. Now I have one more question about that. In the attachment, the book talks about (1-cos(theta))=2sin^2(theta/2) gives the magnitude of R as R=2Asin(theta/2). I don't see how they jump from the first equation to the second. Can anyone explain?
Homework Statement
what is the resultant vector of an isosceles triangle?
Homework Equations
R^2=a^2+b^2-4abcos(theta)
The Attempt at a Solution
The books answer R=2acos(theta/2)
Using the formula above, and knowing that a=b in a isosceles triangle I am getting...
I am trying to teach myself physics. I have been going through the book "physics for scientists and engineers" by serway and jewett and doing all the problems in the back of the book and comparing my answers with the solution manual. I also downloaded all the physics lecture from MIT and Yale...
Homework Statement
Liz rushes down onto a subway platform to find her train already
departing. She stops and watches the cars go by. Each
car is 8.60 m long. The first moves past her in 1.50 s and the
second in 1.10 s. Find the constant acceleration of the train.
Homework Equations...
Homework Statement
The integral from v=vi to v of v^-2dv = -3 integral from t=0 to t of dt
Homework Equations
The Attempt at a Solution
I am getting -1/v + C=-3t and the book is getting -1/v+1/vi=-3t. Not quite sure where they are getting 1/vi as I am getting C.
Ok, that made complete sense. I am a bit rusty on my math and forgot when you factor "t" out you get two solutions. But i am having trouble visually imagining this. Say you visually imagine x position graph. If there is no change in x horizontally (when x(initial)=x(final)), you would have a...
ok, so what I said is correct for horizontal movement but not necessarily true for vertical moment, correct? I still do not see how the book is getting the time formula from observing that equation.
So my physics book says "from x(final)=x(initial)+V(initial)t+1/2at^2 observe that when x(final)=x(initial), the time is given by t=-2V(initial)/a"
Now if change in x is equal to 0, wouldn't your velocity v(initial)t from above along with your acceleration also be zero?
How is the book getting...
So h=1/2gt^2. I am having some trouble understanding this equation.
Here are my questions:
1. I know you get two completely different answers if you plug in a set value, but why can't you measure height of a free-falling object by multiplying the number of seconds^2 times 9.8m/s^2?
2. Is...