# Search results

1. ### Forces of Friction question

So what you're saying to do is Fn= 60cos15 - 60cos15 ? Then the answer is automatically 0 or undefined.
2. ### Forces of Friction question

1. A boy drags his 60.0N sled at constant speed up a 15 degree hill. He does so by pulling with a 25.0-N force on a rope attached to the sled.If the rope is inclined at 35.0 degrees to the horizantal, (a) what is the coefficient of kinetic friction between sled and snow? (b) At the top of the...
3. ### Molar Conversions

Which will have the greater number of ions, 1 mol of nickel (II) or 1 mol of copper (I)? 2. No equations 3. Nickel: 1 mol/58.69 g of Ni * 6.022*10^23 ions/ 1 mol = 1.03 * 10^22 ions. Copper: 1 mol/ 63.55 g of Cu * 6.022 * 10^23 ions/ 1 mol = 9.48 * 10 ^ 21 ions. Nickel will...

5. ### Chemistry Chemistry molecular shapes prob.

1. Determine the shapes of Br2 (2 Bromine atoms) and HBr. Which is more polar and why? 2. No equations. 3. Okay, I know that Br2 and HBr molecule shapes are linear (I know how to draw them) but I do not get how to find which one is more polar. :confused:
6. ### Another related rates problem

The volume V of a cone (V = 1/3*pi*r^2*h) is increasing at the rate of 28pi cubic units per second. At the instant when the radius r of the cone is 3 units, its volume is 12pi cubic units and the radius is increasing at 1/2 unit per second. At the instant when the radius of the cone is 3 units...

Kay, thanks.
8. ### Related Rates triangle area

Okay, I got stuck again. DL/dt*W+ L*DW/dt = 0. 4*W + L* -.5 = 0. How do you find L? Once you find L, isn't it obvious what W will be? Then you wouldn't have to go through this whole rate problem.
9. ### Related Rates triangle area

Never mind, I totally forgot about the product rule.
10. ### Related Rates triangle area

1. A rectangle has a constant area of 200 square meters and its length L is increasing at the rate of 4 meters per second. Find the width W at the instant the width is decreasing at the rate of 0.5 meters per second. 2. Know: dL/dt= 4 m/s, dW/dt=.5 m/s Want: W 3. LW=A. Then DL/dt...