Multiply 1/(square root of 3) by the (square root of 3)/(square root of 3). Leaving you with the square root of 3 in the numerator and 3 in the denominator. Then multiply that by 2/1 (same thing as 2) to give you 2(square root of 3)/3.
How did you think I rationalized?
Can someone please explain to me how to use this and give an example that we can walk through please? My book doesn't give an example of what it is talking about.
~Kitty
I get how to do it and that is the process that I used exactly. I just need to know if my answer is correct. That example does tell me I'm going through the correct process though. I was walking blind through the book. :smile:
~Kitty
2( square root of 3)/ 3 I believe they are equivalent answers. I think they might have mislabled the answers again. This book is notorious for doing that.
~Kitty
When I do 1/(sin 2.5) I get 1.69 for answer. How do you know when an answer is within limits? Like my answer is .02 different than yours. Does that mean its wrong?
~Kitty
This might look kinda messy but this is one of the problems I've been working on sec^2xdx in the intervale of -pi/6 < x < pi/6. Does that make sense?
~Kitty
No I don't think you are.
The only other thing I can't figure out is why I keep getting the incorrect answer because I'm following the process of the Fundamental theorem of calculus the way my book tells me too down to the letter. Is there some reason why this keeps happening?
~Kitty
Right. What I do when I have 1/sin x questions is I do the trig first so the sin x then once I have that answer I divide one by the answer I get. Is that still wrong?
~Kitty
Oh I forgot to ask this...is it possible to take a secant function on a calculator? My Calc teacher informed me that the secant function and 1/cos (or whatever the correct inverse function is) is not the same when you do them on the calculator. Once you do the initial function like cos, sin...