Multiply 1/(square root of 3) by the (square root of 3)/(square root of 3). Leaving you with the square root of 3 in the numerator and 3 in the denominator. Then multiply that by 2/1 (same thing as 2) to give you 2(square root of 3)/3.
How did you think I rationalized?
I get how to do it and that is the process that I used exactly. I just need to know if my answer is correct. That example does tell me I'm going through the correct process though. I was walking blind through the book. :smile:
No I don't think you are.
The only other thing I can't figure out is why I keep getting the incorrect answer because I'm following the process of the Fundamental theorem of calculus the way my book tells me too down to the letter. Is there some reason why this keeps happening?
Oh I forgot to ask this...is it possible to take a secant function on a calculator? My Calc teacher informed me that the secant function and 1/cos (or whatever the correct inverse function is) is not the same when you do them on the calculator. Once you do the initial function like cos, sin...