Homework Statement
L[cos(at)cosh(at)] = ?
Homework Equations
L[cos(at)] = s/(s^2 + w^2)
The Attempt at a Solution
I'm able to get the solution given that is (s^3)/(s^4 + 4a^4)
The question requested to use first shift property. So I used cosh(at) = 1/2[e^at + e^(-at)]...
simplify f(x)g(x) using simple algebra properties first then only apply some log rule like log ab = log a + log b
i'm not too sure if d/dx log ab = d/dx log a + d/dx log b, but you may give it a try
sin^2 4@ == (sin 4@)^2
then if u do like normal differentiation, u get 8sin4@cos4@
and with the trigo identity, u will get 4 sin8@
thus, that result would approaches 0 for @ --> 0
ps: sorry, don't know how to use the mathematical notation thingy
(x'y'+z')' +z +xy+ wz
= use de morgan's law, (x.y)' = x' + y' | (x+y)' = x'.y'
= take out the common factor, anything +1 = 1
= z.1 + xy
= z + xy
hope this helps
In tutorial classes, they gave a semicircle and that was quite easy to get it... but this geometrical shape triangle... is my first time trying it, and i got so say... its cracking my head (i know its simple stuff...but i really don't get where went wrong)
i'm not sure about the ds part as usually there is this table i would refer to, and it says ds = dxdy z_hat but ... I've also tried doing using it, i won't get the same answer.
If need to integrate over a circle, transform the vector to cylindrical type and use cylindrical variables r phi z...
Hi guys... I'm stuck in this question. Its not a homework nor coursework, just practice. The answer for both is the same, that is -1 ...I'm able to get (a) but (b) ... still wondering what went wrong. Please enlighten me. Thanks in advance.
yes that equation is for the condition to get constructive interference...but for the delta m...i know it can't have the same m, but can't the first point of overlap is when delta m = 2 or 3 or so on?
Hi there, I was doing some past year paper of my coming exam...and I got the answers for the question too, but one part I'm totally blur and can't understand that well... well here goes all the questions and solution:
http://server3.uploadit.org/files/chickens-phyQ.jpg [Broken]...
Hi there, I've been struggling with this question for days :cry: :confused: :grumpy: :yuck: , the first part where they call me to prove that equation, i could do it...the second one i don't know how to do...could anyone help me? how do i find the locus equation? its so confusing... ty in...
Hi there,...this isn't homework..its more to my practical...anyways...from the attachment given..that is the first page of my practical guide...the problem is...on the procedure part...it asked me to plot a graph of lg temp againts t ...if i do so...how do i get the thermal conductivity of glass...
Hi there, I think I've done part (ii)..here goes
Lets say first charge is put at A...no work is required.
Second charge put at B, U (B) = U (AB)
3rd charge put at C, U (C) = U (AC) + U (BC)
4th charge put at D, U (D) = U (AD) + U (DC) + U (DB)
U system = U (B) + U (C) + U (D)...
http://forum.lowyat.net/index.php?act=Attach&type=post&id=46273 [Broken]
Hi there, I've been trying this question quite long but I do not get the answer, could anyone help me?
For part one, i got the answer...
part (ii) ... i saw it in a book saying i suppose to choose a point to get...
Yes I do understand that formula. But in c(ii), it wants the speed at which the ball strikes the block. During a very short period, the ball will touch the block eventhough its a elastic collision...so that's why i assume mu^2 = (m_{1}+m_{2})v but i really don't know if that's correct.
I have a book that gives a formulae Angular Speed as same as the Angular Velocity...is that true?
From what i understand, speed is a scalar quantity...so it only have the magnitude value while velocity is a vector quantity which also shows the direction.
Also, will the average angular...
Oh, let's see,
Q a )Work - The work done by a constant force F when the displacement of its point of application in S is given by the scalar products of F and S.
Energy - Energy enables a body to do work.
I also did b (i) (ii), c (i) ...after that I'm stuck on the following...