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yes but what does it specifically mean by 'drift'. You said the velocity in the 3rd dimension is not a drift.

Can I ask what it means by a drift velocity then?

Would that be an acceleration then?

Why are you allowed to assume the drift is in two dimensions though?

A charged particle drifts in uniform, constant magnetic and electric fields. The electric field, E, is perpendicular to the magnetic field, B. Show that the drift velocity is given by vd = (E×B)/B2 Heres where I get to: F=e(E+vxB)=0 as v is uniform. Therefore E+vxB=0. Take vector product...