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llello
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Linear and Abstract Algebra
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Proof involving surjective/onto and image/preimage of sets
Well f^{-1} : B \rightarrow Y So let x be in B as you said. Now f^{-1}(x) is an element of Y provided that there is some y in Y such that f^{-1}(x) = y . This is where you need to use surjectivity. Hope this helps.
llello
Post #2
Oct 27, 2010
Forum:
Linear and Abstract Algebra
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