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Yes, it does. I hope this discussion will be helpful: https://www.quora.com/Would-the-Photoelectric-Work-Function-be-affected-by-the-temperature-of-the-metal-or-the-initial-kinetic-energy-of-the-electrons-If-it-does-why-does-it

The KE orbiting the nucleus is already in the work function.

Would you please explain in details , why pressure is a scalar, though, pressure = \frac {force}{area} and force is a vector ?

I apologise as my last post (#4) was not the appropriate explanation. If I haven't mistaken, your question is that, initially there is a positive work, and finally a negative work, which are equal to each other. So the mechanical energy should be constant. Actually, it is constant. If you go...

As you can see, at first there is a postive work;

At first, consider the following example: Suppose, you have thrown a ball(mass=##m##) from ground to the sky with velocity ##v##; So the ball has a kinetic energy = ##\frac{1}{2}mv^2## ; After that, the net force on the ball is just the gravitational force which is opposite to the displacement...