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In the last case,when we connect the voltmeters ,my book states that I3=I1+I2 but I am not sure How it came

V1=E- I1R1 V2=E-I2R2 V3=E-I3R3 It's getting bigger to solve as I tried

okay so it makes sense that it shows different readings now...but still How can I proceed if they have different resistance

ideal voltmeter-Which doesn't influence the circuit Real voltmeter-Which has resistance that is not infinitely large Same for battery

Homework Statement We have to measure emf of a battery. We have to voltmeters. Each of them when connected alone across the battery, they read V1 = 0.9V and V2 = 0.6V and when both of them are connected to the battery simultaneously, they both read V3 = 0.45V . What is the emf of battery...

Why don't wires in any circuit touch each other and get short circuited? If two current carrying wires carry charges in same direction then from ampere's law,can't they touch each other due to attractive forces?

Got that

I have read it sir...I understood that part about the maximum stress

The tension will be - (mg/L)*x where x is the distance from the bottom Elongation...it should be the force causing the elongation ...in this case the weight so it is (W/AY)dx where dx is the length of the segment

I think the book considers the bar and wire to be same because they have done the integration using the weight per unit length

Yep.It's the weight of the bar...I kinda mixed the wire from the first case In the second case,some stress will be acting because the width gets elongated...I have heard that young's modulus makes sense when stress and strain are proportional. In the second case,the wire is acting along the...

In the second case,the wire gets elongated but the restoring force that is tension remains constant but it;'s width get elongated so will stress also act in that case?

Makes sense then.So the uppermost point is most probable to break first So the strain will not tell us the condition for breaking but the stress will,right? If the breaking stress is equal to the external force (weight) at the topmost point then beyond this the wire breaks,right? What does...

Since at the top,the maximum tension acting on is the weight of the wire mg (Why are we calculating this for the upprmost point tho) If at breaking stress,it has to elongate before it breaks then can we use the formulae of strain here maybe

Since the stress is magnitude of the internal restoring force per unit which in this case is the tension then it will be greatest at the top How exactly did you know to apply the formulae for strain in the second case...I struggled a lot for that My definitions prior to solving a question...

Homework Statement 1) calculate the longest length of steel wire that can hang vertically without breaking .breaking stress for steel=7.982*10^8N/m^2 and density of steel(d)=8.1*10^3kg/m^3. 2)A bar of mass m and length l is hanging from a point A as shown in the figure.Find the...

So I can think of unpolarised light as conissting of many polarised lights perpendicular to the direction of wave direction...? Can we do components of these polarised waves in any two perpendiular direction?

are these wavesof a single light wave or of multiple light waves

Looks like I misread the question...my mistake. I think it should be (A) then

Dispacement is the vector not distance.It should be (c)

Homework Statement How does this picture represent a unpolarised light? Homework Equations The Attempt at a Solution [/B] I thought light waves were perpendicular to the direction of propogation so if it has diagonal components then isn't that not perpendicular to the wave direction...

So by shfting by dt of the magnetic or electric field will tell us the direction

Is it because of kx+wt or is it part of the question?

But in my question,why does the wave travel in -x direction

Homework Statement [/B] In this question, it asks for the magnetic field associated with the electromagnetic wave. Homework Equations The Attempt at a Solution The magnetic field is perpendicular to Electric field but it can be in either x or z direction...how do I choose the direction.I

Yea.I was actually aiming for that only but later I realized It wasn't going to help me. Thanks for the help

Okay. The current in the moving coil ammeter is given by S=Ig G/I-Ig Using this ,I calculated the current through the galvanometer which came out to be 11 ig when I plugged S=G/10

1/4 times the galvanometer resistance in my opinion

All the major current will flow through the shunt while the same current ig will flow through the galvanometer but my textbook says it will show a deflection of I in this case so I was just confused here. I see now that the sensitivity will get changed due to change in current So here since...

Homework Statement An EM wave from air enters a medium. The electric fields are --> ^ E1 = E01 cos(2πv(z/c-t) x --> ^ E2 =E02cos(k(2z-ct)x in a medium ,where the wave number k and frequency v refer to their value in air.the medium...

The current through the galvanometer increases and it's value is 11ig(full scale current) tho idk why it gets increases ...? The deflection will be more in the second case

It starts working as a ammeter

Homework Statement If a shunt of 1/10th of the coil resistance is applied to a moving coil galvanometer,then it's sensitivity becomes (a)10 fold (b)11 fold (c)1/10 fold (d)1/11 fold Homework Equations ϕ / I = NAB/L The Attempt at a Solution [/B] So sensitivity gets increased by only...

I am getting R=r1-r2

So the potential difference across the interal resistor issame as terminal voltage of the battery?

E-2 E r1 /(R+r1+r2)

E-Ir1

E=2E/(R+r1+r2) r1 But why are solving for the terminal voltage of the battery?

2E/R+r1+r2

Potential difference across r1is Er1/(R+r1+r2) so for zero potential difference r1=0 which looks weird

Homework Statement Two cells of same emf E and different internal resistance r1 and r2 are connected in series to an external resistance R.The value of R for which the potential difference across the first cell is zero is given by (A) R=r1/r2 (B)R=r1+r2 (C)R=r1-r2 (D)R=r1r2 Homework Equations...

Since the L=5λ/4 and putting λ=1 ,I am gettting 1.25m

Okay so my length came 1.25 m so what does the extra length tell us?? How should I proceed to do for the water case? Also sorry for my typo...(^|^)

I am so sorry...it was indeed my mistake

I made a mess there...only odd values of n will be alllowed there so I should have used a different variable for that I n any case the value of n will be 3 Initially the tube won't be in resonance. (What does this mean)

Homework Statement In a resonance tube experiment, a closed organ pipe of length 120 cm resonates ,when tuned with a tuning fork of length 120cm resonates,when tuned with a tuning fork of length 340 hz.If water is poured into the pipe ,then (speed of sound in air=340 ms^-1) (A) minimum length...

Okay.I got this then Thanx

And what does this case look like...are we holding the rope?

What is the difference between freely hanging rope and this case? I will keep in mind to mention the units next time .

Change in tension in a rope having masses incrases linearly throughout the rope