I have a hard time understanding how the radial tooth clutch function when it stops transferring power .
Basically I understand that clutches:
1) transfer power from input shaft to output shaft
3) disengage when the torque transmitted has reached a certain limit ( normally when the...
5 is the input shaft
1 is the output shaft
on 1 there is a friction disk mounted (not repesented) so there is a friction between the friction disk and the friction surface
the friction surface is connected to the input shaft through a housing which transfer power.
for the the middle...
I need to identify the elements of the following safety cluches: we have three different clutches.
I lready identified most of them exept for number 14
Any help would be appreciated !
1- output shaft
5- input shaft
I´m trying to solve the following exercice
I have done the following drawing for the cross section
and I want to know if I need to add a top view or any other additional view? (is the cross section enough)
Thank you here it is
we have an isoscele triangle
as you can see the first side is the some of the R1+R2=48
I got the other side by Pythagore
48^2-25^2=1679 means the side value is 40,97
and then the angle =invers.tangente(25/40,97) =31,38°
i´m trying to find the Force applied by the upper roller to calculate the contact surface.
Here is indeed my solution
FR1=878,57N (which is wrong the correct solution says 818,1N)
FR1 is the force normal to the surface of contact.
any help would highly...
in the case of one simple surface the direction of the path determine the orientation of the surface with the right hand rule, in this case we have two borders if one gives us a surface with an orientation that goes with N and the second with one negative with N I hope you got my point
the solution is the following which I understand
I do understand why the current orientation of the Path is positive regarding to stocks (the surface should remain to the left) but I don´t understand why the current N vector of the surface is positive regarding stockes theorem...
As you could see the moment try to make beam to rotate in the support plane with the wall which mean for me this moment is on the Z direction but the longitudinal axis is the X direction and I know that for a moment to be torsion it needs to be in a longitudinal direction, but the...
I used an online software to calculate the reactions and I got the same results if my initially supposed directions are correct.
(ignore the fact that I inverted the bearings here as I´m not calculating forces in the x directions right now)
thanks a million! you mean that my feeybody diagram is wrong? if so this might explain why my results are wrong?
Could you tell what are the wrong directions?
yes the exercice ask about the the reactions on the the other plane by I can solve them once i fix this first!
thanks a million!
for Ft1 :we started by calculating the torque of the motor
Cm =power motor/Wmotor=194,26Nm
then Ft1 =Cm/r1
with r1=(z1*m/2) m is the modulus of the gear
we got FT1=6167 N.
we calculated w6 the velocity of the load 2 with the gears ratio we got w6=18,75 rad/s
Greetings, I have tried to find the reactions of the bearings on the Y direction in the intermediate shaft. but I couldn´t find the numerical results of the solutions
here is my attempt:
in order to find the forces I did the moment equilibruim around the point A and B
With FT1 FT2 and...
I already have the solution, I just want to understand the intuition behind it, like for example if it was a circuit would be in parallel or in serie, I undertand know that it´s in serie and that the total power goes to the intermdiate shaft before it´s splited between load1 and load2
My problem is to understand the flux of power inside this gearbox
for example I can´t understand why the power in load 2 and load 1 are not equal to the power of the motor (suppose 100% efficiency). if this gearbox was an energy circuit (how to know that the energy is transmitted and...
I want to caluculate the summation of this following serie
I started by removing the 4 by
and I thought of the taylor expansion of
Log(1-x)=-∑xn/n but as the 2 is not inside (-1,1) I couldn´t use it