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1. ### What's the total resistance in this circuit?

We take R₃ and R₄, which are parallel, compute resistance which is R/2, and replace with one resistor. Now this resistor is series with R₂, compute again and we get 3R/2. This resistor will be parallel with R₁, thus Rₜₒₜₐₗ=(1/3R/2+1/R)⁻¹=(2/3R+1/R)⁻¹=(5/3R)⁻¹=R*3/5.
2. ### What's the total resistance in this circuit?

I think R₁, R₃ and R₄ are parallel, then we calculate total resistance of these resistors which is R/3, and now we are left with two 'main' resistors in series, we add them up and get R*4/3
3. ### What's the total resistance in this circuit?

I edited subscripts. How can I collapse parallel/series resistors into one when single resistor is parallel and also series, depending resistor I consider it with.
4. ### What's the total resistance in this circuit?

Thanks for the tip. So "a" is branching location (the image again, PS: i couldn't upload local image, so i have to use off-site link), because charge can choose which branch will it flow, and also in each branch here should be one resistor otherwise they would be considered series, so that...
5. ### What's the total resistance in this circuit?

Homework Statement https://imgur.com/3H3pCkD R is the resistance of each resistor, determine total resistance in the circuit. (see the image in the link above) Homework Equations R=1/R₁+1/R₂+1/R₃+... (in parralel circuit) R=R₁+R₂+R₃... (in series circuit) The Attempt at a Solution I'm...