We take R₃ and R₄, which are parallel, compute resistance which is R/2, and replace with one resistor. Now this resistor is series with R₂, compute again and we get 3R/2. This resistor will be parallel with R₁, thus Rₜₒₜₐₗ=(1/3R/2+1/R)⁻¹=(2/3R+1/R)⁻¹=(5/3R)⁻¹=R*3/5.
I think R₁, R₃ and R₄ are parallel, then we calculate total resistance of these resistors which is R/3, and now we are left with two 'main' resistors in series, we add them up and get R*4/3
I edited subscripts. How can I collapse parallel/series resistors into one when single resistor is parallel and also series, depending resistor I consider it with.
Thanks for the tip. So "a" is branching location (the image again, PS: i couldn't upload local image, so i have to use off-site link), because charge can choose which branch will it flow, and also in each branch here should be one resistor otherwise they would be considered series, so that...
Homework Statement
https://imgur.com/3H3pCkD
R is the resistance of each resistor, determine total resistance in the circuit. (see the image in the link above)
Homework Equations
R=1/R₁+1/R₂+1/R₃+... (in parralel circuit)
R=R₁+R₂+R₃... (in series circuit)
The Attempt at a Solution
I'm...
Homework Statement
At the outside, there is a vertical stick with a length of 1.1 meter and its shadow on the surface of an Earth is 1.3 meter, there also is light pole and its shadow length is 5.2 meters, what is the height of that light pole?
Homework Equations
Trigonometry equations to...