ok i still don't think I get symmetry but for the range I've got
{x: x cannot = -90,90,270,...,XER}
this is from tan(theta) not from the equation I wrote in the first post.
If i look at that equation on my graphing calculator i get
{x: x cannot= 0.47, 1.53, -3.76, -4.80.. XER}
the...
HOw does y-3=-\tan (-2x+\pi) differ from y=tan(x)
y=-\tan [-2 (x+ \frac {\pi} {2} )] +3 rearranged
It differs because it has a
Horizontal compression by a factor of 1/2
it is reflected in the x and y-axis
there is a horizontal translation \frac {\pi} {2} units to the left...
Im not sure I think it is either
y=3tan (2(x-60))-5
OR
y=3tan(2x-60)-5
which will become y=3 tan(2 (x-30))-5 but I think this one is wrong
if the first one is right then should the 60 have a negative or plus sign before it?
HELP! QUICK! :cry: :cry:
y=-2\tan (3x+\pi) +3
state the following
period = \frac {\pi} {3}
y-intercept=3
Range = {y: yER}
Domain= {x: ?}
Symmetry?
Vertical Asymptotes?
Zeros?
Can someone please tell me how to figure out what is left there are so many zeroes and i can't read them off of my...
How does the graph y=-3 \cos (2\theta+ \frac {\pi} {4}) +3 Differ from the graph of y=\cos\theta
I think this graph is different because it has a vertical stretch by a factor of 3 and is translated upwards 3 units but I am not sure how to rearrange this to find the horizontal translation...
I needed to find the properties of this trig function this is what i got
period=3
amplitude=0
max=2
min=-2
range{y:-2<=y<=2}
domain {x:XER}
horizontal phase shift 1 unit left
no vertical shift
Are these values correct? Should period have a unit with it or is just 3 fine? What about...
Find the equation of a sine function that has a vertical displacement 2 units down, a horizontal phase shift pi/3 to the right, a period of pi/6, reflection in the y-axis and the amplitude of 3.
my answer y=3\sin [-12(x+\frac {\pi} {3})] -2
is this what you get?
How do I rearrange this where do I begin?
y= -2sin [ 2\pi * \frac {(t+1)} {3} ]
I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement
Im not sure how to rearrange the square brackets.
so if this is my equation y= a sin [b(x-c)] +d
if c is positive it shifts to the left and if negative shifts to the right?
or do you put the minus from this equation and the sign of ur question in my case (+) together and then if it is negative move to the left or positive move to the...
I don't think I am confused about radians and degrees some of my trig functions have radians in them so to make things simpler I convert to degrees but in this question i haven't done any converting that 90 is in degrees. :smile:
sorry I added the x in the original function.
Comparison between y=sinx and...
y+3=2\sin(3x+\frac{\pi}{2})
vertical stretch by a factor of 2
horizontal compression by 1/3 no reflection in the x or y axis
30 degrees horizontal phase shift to the left
and 3 units down vertical displacement.
Can someone please check this?
y=2\cos (\frac {-1} {2}x + 90 ) -3
I changed the original function to
y=2\cos [\frac {-1} {2} (x-180)] -3
period=-4pi
amplitude=2
max=-1
min=-5
range={y:-5<=y<=-1}
domain={x:XER}
vertical displacement 3 units down
horizontal translation 180 units left
y=-3sin(2x) is shifted to the left by 30 degree units and up 5 units
My new equation looks like this I am not sure if I did it right
y=-3sin[2(x-30)]+5
what do you think?
Hi just need a little help with the behaviour of this trig function
y=-3\cos (2x-\frac {\pi} {6}) +1
I converted the pi over 6 to degrees and got -30
need to state the period, amplitude, max/min values, range, domain, horizontal phase shift, and vertical dispacement.
So far after...
Nope i meant focus not locus p stands for the focus of a parabola i don't understand what to do with all those equations. Can someone tell me how to solve for p?
Well yes I think I do know two more points
(0,-50) and (0,50) what do I do to complete my standard form equation?
Do I sub in one of the points into x^2=4p (y-20) and then solve for p?
I don't think I'm doing this right
x^2=4p (y-20)
0^2=4p(50-20)
0=4p(30)
0=120p
now...
I need to find the equation of a parabola in standard form if the domain of an arch under a bridge is {-50 <= x <= 50} and the range is {0<=y<=20}
The span of the arch is 100 metres and the height is 20 metres.
standard form of a parabola is
(x-h)^2=4p(y-k)
i know the vertex is...
According to Halls of Ivy's good solution are my dimensions in the last post correct? For the dimensions do i have to write a number by a number or just the equation of the ellipse?
in cell E3 i have =E2+C3-B3 i think that is the same as what you wrote I don't understand why the balance isn't decreasing help me out where is my mistake I followed an example in putting in all the formulas :smile:
Hey my teacher told me the payment numbers should be 1-60 not 1-5 because...
ok in my table that i made
my heading are in the A1, B1, C1, D1 and E1
the first payment number 0 is in A2 and the oustanding balance 90000 for the first payment is in E2
I don't understand where you got a cell called E0? If you multiply 90 000 by the interest rate on a calculator you get...
the 100 is positive because you did what? :cry:
are we cross multiplying? or multiplying both sides by -100? what are we doing?
That equation i wrote has a negative sign too did u see that? before the brackets.
it can't be +100 on the rhs because this is the equation of a hyperbola. Using the information givin I am trying to find the equation of the hyperbola that could represent a arch with a span of 100 metres and maximum height of 20 metres. I was trying to solve k so that I could sub this value...
hold on i changed what I did
-\frac {(20-k)^2} {100} = -1
ok I cross multiplied and got
400-40k+k^2=-100
k^2 -40k+500=0
this is my quadratic using the quadratic formula i keep getting a negative under the square root why? b^2-4(a)(c) sqrt(-400)
teacher said that k=10 and...
ok I get \frac {k^2 +40 k-400} {100} =-1 is it possible to solve for k? once I find k i can plug it into the original equation to get a and then my standard form equation for the hyperbola representing the arch will be complete.
i got h=0 and y=20 because the coordinate (0,20) is on the y-axis
a cancels out because 0/a^2 =0 so only left with k as unknown get a quadratic function and get two values for k, which value do I take? choose a point let's say (0,50) and find a, these are the steps i have so far.
Um for k...
Your task is to design a curved arch similar to the a tunnel for cars. with a horizontal span of 100 m and a maximum height of 20 m.
Using a domain of {x:-50<=x<=50} and {y:0<=y<=20} determine the following types of equations that could be used to model the curved arch.
the equation of a...
sorry I edited my post i meant present not future. I don't if I am doing the next part right, my next question said create an amortization table for the first 5 years of the mortgage, and include a graph showing the declining balance at the end of each year.
Here is what I have in excel...
I think i understand on the x-axis the points of the vertices are (8,0) and (-8,0) I was wondering how do you know the hypotenuse of the right angle triangle is 4m? a=4m is the hypotenuse also a? My foci should be at (-2,0) and (2,0) right? I got the equation of the ellipse to be \frac {x^2}...
oh yes now i remember thanks the graphing calculator finds the nominal rate itself but if you were to do this using the present formula i'd have to plug in the nominal interest rate. Thanks so much
This is a conic application question worth 8 marks
You don't want your dog to run away so you place 2 steaks in the groud 4 metres apart and attach the end of a 8 metre long rope to each side of the stakes then you attach the dogs collar to a ring which slides along the rope.
Describe the...
ok I think I understand that this is not a simple annuity but a general annuity therefore we have to find the nominal interest rate which was 8.546% compounded monthly is equivalent to 8.7% compounded semi-annually.
Andrew you did this but I don't understand how my answer is right then...
\sum_{i=7}^{92}(-7)^{i+7}
the exponent is i plus 7 not minus. Also the answer is 86 not 85 but I don't know how to get the answer I tried so many times.
I have a question is sigma notation
92
E (-7)^i+7
i=7
Is the number of terms in this series 99? Or
86, 89, or 96 I am so confused PLZ HELP IMMEDIATELY
I think it is 99 because 92+7=99 but I am not sure
I changed my numbers a little and got a little more reasonable monthly payment
n=300
I=8.7%
PV=90 000
PMT=0
FV=0
P/Y=12
C/Y=2
When i pressed alpha solve on PMT i got my value to be -$727.52 :smile: Can someone help me out?
yes I know to write the answer without the negative but I am not sure if the value is right and how to get it without the graphing calculator, I tried to find the nominal interest rate if that is needed it was 8.546%/a compounded monthly is equivalent to 8.7%/a compounded semi-annually. :smile...
The current interest rate is 8.7%/a interest is compounded semi-annually and calculated monthly. The couple that is borrowing $90 000 for their new home wants to know how much it will cost them each month to pay off the loan. Assume they will make one payment per month. Calculate the monthly...