@valhakla What circuit analysis methods have you learned? Have you covered KCL, KVL? How about mesh and nodal analysis? Perhaps delta-Y and y-delta transforms?
Hi Lay1.
I believe that your redrawing is correct, although I can't quite make out the resistor symbols. I think that R8 is the one shown here?
Not sure what you mean by "passing through R8" though.
There are several ways to redraw the circuit, here's an example that isn't far from the...
Sorry, but I can't quite make out your figures in the image provided. I believe that you're trying to form the partial resistance over the total resistance for each of the points A,B,C,D? For example:
If the total voltage is ##6 V##, and ##R_T## is the total resistance, then the voltage at...
@Lay1 combined the two sources into one, so the image in the picture is okay, it just didn't mention the additional step.
One way to do this problem is to first work out the total current and then use KVL around the loop, adding in the successive resistors as you go. For example, finding the...
Consider the segment between B and C. The velocity of the cart is constant, so acceleration is zero. No work is being performed there. Next consider the segment between C and D. What happens there? Is acceleration increasing, decreasing, or constant?
I suspect that they're looking for the pulley's angular momentum. But since the rotation of the pulley will increase without limit (assuming ideal components without limiting factors), you might want to express the angular momentum as a function of time.
In cgs the unit of charge is the electrostatic unit, or esu. The constant in Coulombs law is set equal to 1. Therefore, two charges each with charge 1 esu sitting 1 cm apart will feel a force between them of 1 dyne.
You can redraw the circuit to make things clearer. The endpoints a and b can be moved anywhere along the lines they connect to, so move them to the bottom and top points as follows:
Then straighten out the bends to make the image more clear:
You should be able to work out the combined...
I think you'll want to take a closer look at the current divider expression. Let's say you have two parallel resistances A and B with some total current ##I## being split between them. Then you can write:
##I_A = I \cdot \frac{B}{A + B}##
##I_B = I \cdot \frac{A}{A + B}##
Make sure that you...
Hi @johnsmith7565 ,
Welcome to Physics Forums.
Note that the ##60 Ω## resistor is not in series with the ##40 Ω## and ##80 Ω## resistors; The existence of the resistor ##R## precludes that.
What you can say is that 20 A enters the top node from the direction of the source, and that it must...
How is the electric field oriented around a (long) charged rod? Is there a symmetry involved?
Would you expect the field to be of even magnitude over the surface of each side of the cube? How about the sides that the rod passes through?
What does Gauss' Law have to say about the total...
Hi xwalsh, Welcome to Physics Forums.
Have you drawn a Free Body Diagram (FBD) for the block to show the forces acting? What does it tell you about the net force acting on the block?
If the two voltage dividers behave identically at the given frequency, then adding equal resistors in equivalent locations will have identical results for each path.
If you ignore the resistors for a moment, you'll see that you have a pair of voltage dividers consisting of series-connected L and C. What can you say about the reactances of L and C if both arrangements are to produce identical potential drops at their junctions?
Your intuition regarding the maximum current not exceeding the initial 9 mA is correct. We also don't expect any big back-emf spikes to occur since the inductor never "sees" any abrupt open circuit conditions during the switching operation -- there's always a continuous circuit for its current...
If the object is to find the power produced by that dependent current source, then there may be an easier way to find it than analyzing the whole circuit to find ##V_x## and ##I_x##.
By inspection of the circuit, what must be the potential difference across that current source? Hint: look at...
While at school I was introduced to several conventions for source representations. This "arrow beside a circle" was one such. The arrow is meant to represent the direction of increasing electric potential, and is not necessarily indicative of the direction of current flow.
We've all seen...
@Butterfly41398 , it's very difficult to make out the contents of your images (the handwritten workings), so I can't really help spot any errors. You'll have to clean up the images to make them useful, or better yet, type out the work so that others can quote it in replies.
The first equation gives you the node voltage. That's fine.
The second equation will then correctly give you Im. So that's fine, too.
The third equation you need to be careful with the current direction of Ir. It's shown as flowing into the node, so technically:
##Ir = (0 - Vparallel)/Zr...
With the current directions you've defined in the diagram, KCL at the node would yield I am = Is + Ir, no?
Note that ##i_1## flows in the same direction as Im, while ##i_2## flows in the opposite direction. So ##Im = i_1 - i_2##.
Considering that the circuit represents a generator, it is not unreasonable to find that it produces a current "out" of terminal a.
I can confirm that ##Is## as labelled on your circuit diagram has negative component values as you've found. I used mesh analysis to find the currents:
In the...
Where does ##Xm## come from? You didn't list an inductance value above. I presume, given the value, that it corresponds to a 100 mH inductance?
Careful here. You've used the magnitudes of the previously calculated values, losing the inherent phasor information of the complex values. Then...
Hello jay. By forum rules you'll need to show us exactly what you've tried before we can offer help. We need to see what your current understanding of the problem is.
How might the polarity of the circuit's voltage source effect your results?
It is unfortunate that the circuit diagram does not make it clear how to interpret the polarity of Vout where it is labelled.
Your Vth value looks good, an exact value being 25/21 V. However I disagree with the value of 10 Ohms for Rth.
Consider what happens if you place a short circuit across the output. In that event Vx is forced to zero and so the current source produces zero current and the 60 Ohm resistor...
Hi. It looks like you've correctly found the equivalent impedance and the magnitude of the current (both without units though). However, you'll need to account for the phase angle θ of the source in your Io.
In order to explore where you might be running into difficulty, perhaps you might begin by describing your understanding of the prescribed method for find the Thevenin equivalent of a circuit. For now, we assume that only fixed value sources are in play -- no dependent sources or other...
The problem doesn't directly state whether or not the capacitor is isolated or connected to a constant source voltage (to maintain a constant potential difference as the plates are moved). The relevant equation intimates that the voltage is held constant, but as it is a relevant equation and...