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Homework Statement Referring to (b) in the picture above: What is the direction of the magnetic force on the electron? Homework Equations I use the right-hand rule where by putting your index finger in the direction of the magnetic field and thumb in the direction of the velocity, the middle...

Homework Statement In the attached file, how do I decide which side of the resistor is positive/negative? Homework Equations N/A The Attempt at a Solution The current would go through the 6V battery starting from the positive end of the 9V battery to the negative end of the 9V battery; so my...

Thank you for pointing that out. I edited it now. If I were to sketch, I would draw the electric potential increasing from the negative to the positive end, and the electric field vector going from the positive to the negative end. I think I am mainly confused about where I should put the...

Homework Statement The electric field inside a parallel plate capacitor is measured to be E= -3500 N/C i. The electric potential at point XA = 3.00 m is measured to be 1500V. What is the electric potential at point XB = 0 m? Homework Equations V=E⋅s The Attempt at a Solution I think I need to...

I believe 4Ω and 48Ω resistors are in parallel. Req = (1/R1 + 1/R2 +...) -1. But how would this help solve the problem? I tried drawing it in two different parts, but I'm not sure how to combine the two, if they are right.

Homework Statement Find the current and potential difference through 3Ω resistor. Homework Equations ε - I1 (Ω) - I2 (Ω) ... = 0 The Attempt at a Solution I only got as far as finding the equation: ε - I1 (3Ω) - I2 (16Ω) = 0 (For complete loop around circuit) I know I have to find I1, but I...

Thank you for your explanation. Which formula should I use if I am solving for the electric field due to finite line of charge?

Homework Statement The problem I encountered goes like this: A 10cm long thin glass rod uniformly charged to 10nC and a 10cm long thin plastic rod uniformly charged to -10nC are placed side by side 4cm apart. What are the electric field strengths E1 to E3 at distances 1cm, 2cm, and 3cm from the...

To find the x component, E=[(8.99⋅109Nm2/C2)(6⋅10-9C)(0.447)] / (√0.052+0.12m)2 = 1928.8944 N/C To find the y component, E=[(8.99⋅109Nm2/C2)(6⋅10-9C)(0.894)] / (√0.052+0.12m)2 = 3857.7888 N/C However, despite using these values, I still get the same answer as my first attempt: xnet= 10788 N/C...

The electric field vector of the positive charge only has an x component, which I already have calculated. However I am not quite sure how I would find the x and y components of the electric field from the negative charge if I do not have any information about an angle in the first place.

Homework Statement The diagram is attached. What is the strength of the electric field at the position indicated by the dot in Figure 1? What is the direction of the electric field at the position? Specify the direction as an angle measured clockwise from the positive x axis. Homework...

Homework Statement A -12nC charge is located at (x,y) = (1.0cm, 0cm). What are the electric fields at the positions (x,y) = (5.0cm, 0cm), (-5.0cm, 0cm), and (0cm, 5.0cm)? Write each electric field vector in component form. Homework Equations E=k(q/r2) The Attempt at a Solution I was able to...

I am not sure, would the distance from the half point to the top simply be 125.66/4? If that is right, then energy lost = 62.83 (approximately) ?

How far the car travel would be the circumference, so : C=2πr = 2⋅π⋅20 = 125.66 (approximately)

The second equation shows that, but what I did was (before using the second equation) I tried to find the curved distance of the path from the middle point to the top point because the question indicates "2.0J per meter of track". By finding the distance traveled I can multiply that by 2.0J to...

Homework Statement If the car is going 30 m/s half way up the loop and loses energy due to friction at a rate of 2.0J per meter of track, how fast will it be going at the top? (this is question related to the loop of roller coaster track, with radius 20m.) Homework Equations 1. Ki + Ui = Kf +...

Yes, sorry, I meant kinetic energy.

Homework Statement An object of mass 100kg is acted on by a constant force as it moves through a displacement at a constant speed of 7.2m/s. What is the net work done on the object? Homework Equations Wnet = ΔK Fnet = 0 The Attempt at a Solution I know that the answer is zero because the...

Homework Statement Please look at the screenshot attached. The answer is "Yes", but I am not sure why. Homework Equations N/A The Attempt at a Solution Oxygen have six electrons, but the energy diagram shows only five. That was why I thought it was wrong, but the diagram shown is correct...

Is the force a part of action/reaction pair?

Homework Statement A person of mass M is walking across the ground carrying a heavy bucket of water of mass m on top of their head. Which of the following forces is not acting on the person? a) The gravitational force on the person Mg acting downward b) The normal force from the ground acting...

That helped a lot, I realized I have to use some kind of formula for that relationship between the two situations. I was able to get the answer to the question. Thank you!

½ k ⋅ Δx2 = ½ mv2 When potential energy is doubled, k ⋅ Δx2 = mv2, so v= √[(k ⋅ Δx2)/m] This is the same velocity as when there is only one spring. So would the speed for both situation be the same?

Homework Statement The spring in the figure (Figure 1) is compressed by length Δx. It launches the block across a frictionless surface with speed v0. The two springs in the figure (Figure 2) are identical to the spring of figure 1. They are compressed by the same length Δx and used to launch...

Homework Statement A particle that can move along the x-axis experiences an interaction force Fx=(3x2−5x) N where x is in m. Find an expression for the system's potential energy. Express your answer in terms of the variables x and the constant of integration C, where C is in joules. Homework...

Oh I read the question wrong. Thank you, I got the right answer this time.

Homework Statement The question is as follows: A 50kg ice skater is gliding along the ice, heading due north at 4.0m/s. The ice has a small coefficient of static friction, to prevent the skater from slipping sideways, but kinetic friction =0. Suddenly, a wind from the northeast exerts a force...