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I understand ur point. So is the approach right? And how about answer?

so acceleration is negative...

Acceleration reduces as the bullet enters the target.

@willem2: How is tat? can you please elaborate.

A bullet of 0.005 kg traveling at 20m/s penetrates deeply into a fixed target and is brought to rest in 0.01 sec. The distace through which it penetrates is: I used, acceleration= V/t = 20/.01 a = 2000 m/sec sq Distace covered = Ut+0.5 at^2...