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Thanks for your explanation! But,What is meant by this line?

So is it correct to assume this world made up of only one type of charges(electrons)? Would the assumption that only one type of charges exist not affect Gauss Law?

I believe the answer is incorrect, reasons: The answer assumes that electric field will exist . But this is not the case , until and unless there is a bipolarity there cannot be an electric field ( in case of isolated charged objects, the field exists because the bipolarity is separated by a...

If an isolated conductor without cavities is charged, its excess charge will distribute itself on its surface in order to guarantee that the electric field is zero on its interior. If instead the conductor had an interior cavity, the charges would again distribute themselves on the outer surface...

Ok thanks! I can see things getting clear.. But,what actually prevents the electric field lines generated by external charge *to penetrate and get inside* the cavity throght the material of the conductor and make the electric field inside the cavity non-zero? this is my main doubt.

Suppose,we have a solid spherical conductor with a cavity in it and a charge +q placed outside the sphere.Then how is the electric field inside the cavity zero?Can you please explain this?

What is true is that the field due to the point charge outside of the conductor will not be able to penetrate the shell i.e. there will be no field due to the external point charge anywhere within the conductor nor in the cavity: the field will be **killed off*& by the charges on the outer...

My teacher taught me a formula for magnification in case of Compound Microscope, Magnification=(Angle Made By Object On Aided Eye)/(Angle Made by Object on Un-aided Eye) Can I use this formula for calculating magnification of Astronomical Telescope? Thanks!

Do Prism form image? If they do form image, then what is the nature of the image formed?

Is it possible to get a real image of virtual objects, If so please explain with examples and some real life situations? Look at my assertion "rays will not pass through virtual objects so how it can form real image", is this possible, please help.

About what second order term are you talking? Note: English is my second language. I will be thankful for any help!

<Moderator's note: Moved from a technical forum and thus no template.> $$\lim_{x\rightarrow 0} (x-tanx)/x^3$$ I solve it like this, $$\lim_{x\rightarrow 0}1/x^2 - tanx/x^3=\lim_{x\rightarrow 0}1/x^2 - tanx/x*1/x^2$$ Now using the property $$\lim_{x\rightarrow 0}tanx/x=1$$,we have ...

But doesn't 1^infty mean that we are multiplying 1 infinite times and hence the final product must be 1.

I've been taught that $$1^\infty$$ is undetermined case. Why is it so? Isn't $$1*1*1...=1$$ whatever times you would multiply it? So if you take a limit, say $$\lim_{n\to\infty} 1^n$$, doesn't it converge to 1? So why would the limit not exist?

Suppose light rays from an object fall perpendicular to the surface of the plane mirror. Will the image be formed at +infinity(a virtual image) or -infinity(a real image)? I will be thankful for help!

<Moderator's note: Moved from a technical forum and thus no template.> $$\lim_{x \to 0} \cos(\pi/2\cos(x))/x^2$$ I tried to evaluate the limit this way, $$\lim_{x \to 0} \cos(\pi/2\cdot1)/x^2$$ since $$\cos0=1$$ $$\lim_{x \to 0} \cos(\pi/2\cdot1)/x^2=\lim_{x \to 0} 0/x^2$$ Now apply...

Hi All, The Potential Energy for two chemically bonding atoms is defined by ,U=1/2(k*q1*q2)/r So it means that when the atoms approach each other then, their Potential Energy will increase. Where am I doing wrong? I will be thankful for help!

Homework Statement Homework Equations Formula of Kp and Kc The Attempt at a Solution You will easily be able to identify that the reaction will proceed in the forward direction when some inert gas is introduced. So,my question is that why won't the amount of chlorine formed increase in...

Thanks! I got it. One more doubt, At what level shall i consider the gravitational potential energy zero?

Homework Statement Homework Equations Kinetic Energy =1/2*m*v^2 Spring Potential Energy = 1/2*k*x^2 Gravitational Potential Energy = m*g*h The Attempt at a Solution I am thinking to solve this problem using energy conservation but I feel that it is not possible to apply energy conservation...

Thanks ![emoji4]

"How will you compare to someone who is not a clever and works hard? ... You say some things we have no control over, what about your neurons in your brain do you have control over them? Their efficiency, number, synapses, neuro-transmitters? Is the structure and efficiency of your brain less...

In meiosis 1, it is said that chromosome numbers become halved in the two daughter cells. For example, in a 2n human cell there are 46 chromosomes. During meiosis 1, the cell will undergo interphase and probably the S-phase, where chromosome number becomes duplicated. Now the cell is 4n (i.e...

Studying with them is a good idea! Isn't it?

Thank you so much for guidance!

Thanks! I have started to gain my motivation back. It's Physics and Maths

I meant - ""when the coefficient of kinetic friction is greater than that of static friction,then what would the motion of block look like?"

Homework Statement How would the motion of the block look like when the Force of kinetic friciton is more than the Limiting value of static friction? Homework Equations Kinteic Friciton=μN The Attempt at a Solution I think the block after overcoming the limiting value of static friction will...

Thank You everyone for boosting my belief in "Hardwork" back again! One more thing I would like to know is. How does I.Q. affect the problem solving capabilities of a person?Is it influenced by the genetics or can it be improved with practice? I have seen some students with GREAT I.Q. in my...

I asked this because I find myself in situations which trouble me deeply. I solve a deep interesting problem, I learn a new concept, its good but a single question which I'm not able to do, leaves me depressed, sometimes I can't just understand whether I CAN or CANNOT apply a concept to solve...

Man pulls the rope downwards with a force F.So,By Newton's Third Law an upward reaction force F acts on the man. So is the tension produced in the string equal to F?

Is the tension force generated in the Rope,T equal to the force applied by the man?

I'm a little confused with the application of laws of motion on a man climbing a rope. Suppose a man of mass Mg is climbing a rope with an acceleration a. Rope is massless. Now if look through the frame of the piece of rope held by the man, there is a force Mg downward by man, ma downward...

Thanks

But is it possible that F=kx in any condition?

So it means that F=/=kx

F-kx=ma

Yes,F(on right) is a separate force applied to mass m other than the spring force acting on the left side.

No

I am not trying to invoke any law

Is it necessary that the applied force F is equal to the spring force 'kx'?

Suppose a spring of spring constant=K and Length=L is split into two parts L1 and L2, with spring constants K1 and K2 respectively. Then,why is it such that the spring force F=K1*L1=K2*L2=K*L? Please give an intuitive explanation of why the spring force doesn't change? I will be thankful for...

The relation between xi, xj and x would be "xi+xj=x". Please tell how to proceed further!

In the first equation W_gravity on B=1*x*g*sin(37),is it correct now? And in equation 2 It's not "mH",It's (m+1)[sorry!For my poor handwriting] Yes I think there would be a minus sign because the formula for spring force is "-k*x". Is it correct?

I tried solving it this way this time..., I have formed two equations, Are these two equations useful in finding "m"? Or,do I need to find something more? I will be thankful for help!

I think I need to apply the work energy theorem. But on which block ?

It would be zero,Right?

It would be, -0.6x=1*10*sin(37) So what's next?

Homework Statement See question number 1. Homework Equations Work Energy Theorem, work done by all the forces=change in K.E. The Attempt at a Solution I tried solving this question this way, please help me calculate the Work Done by spring here?? I will be thankful for any help!

And this pressure is being supplied by the gas.Right?