# Search results for query: *

1. ### Studying EE textbooks....to keep or not to keep?

So I am junior EE student and was wondering whether i should keep my upper level courses' textbooks or not. I have my lower level courses' textbooks simply because my brother will be coming into TAMU in the future, but I'm confused as to what to do with my upper level books (rent or buy). Here...
2. ### Diffifult RC Circuit

Ahh i see now. Thanks

KCL?
4. ### Diffifult RC Circuit

Find the potential of point a with respect to point b in the figure (Fighttps://s.yimg.com/hd/answers/i/1ffe0f8aeaf145679cde38f7812b1c7f_A.png?a=answers&mr=0&x=1413484693&s=0943630e47eb74ae023909f7d39f74e3 [Broken] ure 1) . If points a and b are connected by a wire with negligible resistance...

thanks!
6. ### Physics lab Hall Effect

In this experiment you will use the Hall Effect to measure the strength of magnetic fields. Which of the following are true statements about the Hall Effect? (Select all that apply.) The Hall probe that we will use in this lab is made of a semiconductor. (check- i know this is one) The value...
7. ### PHYSICS LAB HELP - RC circuit

I tried looking this up but am not sure what you mean? Again we just started RC Circuits so I am a little lost..
8. ### PHYSICS LAB HELP - RC circuit

Consider a series RC circuit with an R = 3.0 Ω and a capacitance of 12 µF being charged to a voltage of 5.0 V. (Note, you will not include units in your answers.) If you wished the charging of this capacitor to have a vertical displacement of 4.0 DIV from 0 charge to fully charged, what value...
9. ### Electromotive Force

Thanks i seem to get it after reading these posts and rereading the chapter! :):):):):):):):):):):):):):):):):):):)
10. ### Electromotive Force

The potential difference between the ends of a wire is given by Vab = IR. Combing that with E = Vab we have E = Vab = IR (ideal source of emf). " That is, when a positive charge flows around the circuit, the potential rise as it passes through the ideal source is numerically equal to the...
11. ### Deriving Units for Current Density - J=I/A Length

Ok i actually see what i was doing wrong. Just a bad algebra error. Thanks!
12. ### Deriving Units for Current Density - J=I/A Length

Units of A: C/S Units of I: A
13. ### Deriving Units for Current Density - J=I/A Length

Just trying to derive the units for current density but i keep getting A*m rather than A/m^2. J = I/A A length derivation would help.
14. ### Spherical Capacitors

A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 10.5cm , and the outer sphere has radius 15.5cm . A potential difference of 110V is applied to the capacitor. What is the energy density at r= 10.6cm , just outside the inner...
15. ### Conductor with shell problem getting zero as answer?

Ahhh makes sense now. Thanks!
16. ### Conductor with shell problem getting zero as answer?

1. Problem Statement: The figure shows a cross-section view of a very long cylindrical cable. There is an outer tube made of copper, inner radius 2R, outer radius 4R. The inner copper wire has radius R and is concentric with the tube. The inner wire has charge density –2λ (per unit length)...
17. ### E-Field and Voltage"

Seems to be clearer now. Just got to practice! Thanks!
18. ### E-Field and Voltage"

Ok i can see how you can possibly just go through with the integration and skip "those" steps, but is there a rule to when you can and cant? I mean the other way works fine for me, cut i really do want to know when that can be done? I can see sort of why.
19. ### E-Field and Voltage"

See that's what my prof said and it sort of made sense then so i went with it (Note to self, if physics makes sense right away, you done screwed up!:(). When i go onto calculate it seems weird.? Ok let me try to explain what i seem to know. "Because E-Field is a vector, you must account for...
20. ### E-Field and Voltage"

1. Looking to find E-field and Voltage (in pic) 2. Coulomb's Law, E=q0V, E=integralde 3. Basically i tried to split the quarter ring into halves and then integrate. It worked i got the right answer. But my professor did it in 1 step? Something about just integrating over DV? I don't get...