maybe i screwed up the math..because that didnt work
0.5*m*v^2=(-u_k*m*g*D)-(m*g*D*sin(6))
9187500=-58860d-146344d
9187500=-205204d
d=12.4
and that was still wrong, and i can't see where i messed up in the math
Truck brakes can fail if they get too hot. In some mountainous areas, ramps of loose gravel are constructed to stop runaway trucks that have lost their brakes. The combination of a slight upward slope and a large coefficient of friction in the gravel brings the truck safely to a halt. Suppose a...
the 2nd part of the problem is w= intergral of { mv*dv} between v_final and v_initial
and we are supposed to express that in m_vinitial and v_final
and i got the answer ((m*v_final)^2-(m*v_initial)^2)/2 and that didnt work. i used the basic intergral formula
fint{t*dt between a and b}...
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Express the acceleration in terms of v_initial, v_final, and s:
that was...
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ok so you...