He said he mostly wanted us to compare it to the potential of an infinite wire, where reference point at infinity can't be taken. I'm guessing there's a natural log somewhere in the real potential function.
There's no obligation for us to turn this in. I went talking to the professor after the test trying to figure out how to do it, but I'm the only one working on this problem still.
Yes, but in order to find the potential from the electric field, we need a function. The only way I know of how to get the electric field at the origin gives a constant that can't be integrated from -infinity to 0
We were told there was a finite solution to the potential by the professor. The electric field is non-uniform and decreasing as it moves away from the origin in the negative x-direction, so if I do work between two points, there should be a potential difference.
What method would I use to...
Each charge has a different magnitude, and they're at different locations, so other than on the horizontal axis, each point charge will have a different direction making a very complicated electric field.
Summary: Potential at origin of an infinite set of point charges with charge (4^n)q and distance (3^n)a along x-axis where n starts at 1.
From V=q/r, we find Vtotal=sum from 1 to infinity of (4/3)^n(q/a), which diverges. There cannot be infinite potential because there is a finite electric...
I'm confused what's meant by a uniform surface current density since this plane has a thickness, It would need a current density distributed through its cross sections, I thought.
Edit: I tried solving with proper LaTeX and all my steps, but it looked awful. For outside, I got B=µ_0jd/2.
for...
In my textbook, it is talking about the Hall Effect on a flat conductor with width w carrying a current i in a uniform magnetic field perpendicular to the plane of the strip. It says that this will create a potential difference of V=E/w where E is the induces electric field from the electrons...
Homework Statement
Homework Equations
V=k∑q/r
E=-dV/ds
The Attempt at a Solution
I found part A plenty fine, 2kq/a
From here, I thought that the derivative of -V would give me the electric field, giving -2kq/a^2, but that's not the answer according to what my professor sent. I'm wondering...