Now here is the part where I'm sort of stumped myself:
Could someone let me know if my reasoning is valid? The professor explained it during office hours and all I got out of that was that something cancels out and the answer is 0.
I don't see a direct constraint on Tmax in this problem that is given. I'm still unclear on what you mean by:
The only constraint I see is on torsional shear, which is a function of Tmax.
I don't understand, but I'll give it a try.
Are you saying to plug 900-T, 1500-T, and 1800-T into the equation, shear=Tc/J and try to maximize the value of T?
Okay, scratch all that. I managed to figure it out by finding similar problems. Thank you for the guidance. I hope that this post of mine is error-free!
We need to start by applying the right-hand rule to the applied torques, with the sign convention that a torque directed away from point E is...
Okay, I reworked the problem. I drew a torque diagram.
It seems that the maximum possible value of the unknown torque, T1, is 327 Nm.
From there, it seems that the internal shear stress in section CD is about 47 MPa, and the internal torque in DE causes the bar to hit its shear stress limit...
I wish to draw a proper free-body diagram for this shaft. However, my FBD does not agree with the solutions manual. If someone could point out where I erred, that would be great.
This is what I drew:
From my FBD, it is clear that the maximum torque is present in section DE of the shaft.
We...
I got a non-response response, so I guess I'll just chalk this up to YET another case of bottom-barrel textbook editors doing bottom-barrel work in writing questions and solutions. Book in question is Hibbeler's Dynamics, 14th edition. I used Hibbeler's Statics text last semester, and the...
It seems that to solve the problem as stated would actually involve finding an equation relating the angle, theta, and the height on the wall, h. And then you would take the partial derivative of height equation with respect to theta to find the extrema.
I'm currently awaiting a response :).
That's a great question, and from my discussions and research, I was told that this assumption is incorrect in this problem.
That being said, the book's solution manual makes that assumption, and so does my Dynamics professor:
But it seems that even if we take this assumption as valid (which...
Using the equations for constant acceleration, we can write the following set of equations for this problem:
We have the following known physical constraints:
Solving the above system of equations and constraints with a computer algebra system:
So, all the solutions I found make...
Thanks, so what's the takeaway here for finding the final position of a particle that lands on a hill?
We have the book, which asks for "(x,-y)," and the book comes up with the "-y" displacement equation.
We have a famous professor on YouTube solving for "(x,y)" and he comes up with the same...
Here's a much more condensed version of what I'm asking: who's correct, the book or the teacher's method?
The points of impact are are in x and y. Time is "t."
Summary:: After firing a projectile from the top of a hill, where does it land on the hill? I disagree with the professor in approach and final result.
Problem Statement:
Relevant Formulas:
Attempt to Solve:
I'm very familiar with these types of problems. I'm not here for help solving...
Problem statement:
Attempt at a solution:
1) There are no relevant moments that need to be drawn in this free-body diagram.
2) There is tension in the chain DE that is pointed away from the truck, i.e. from D to E.
3) There are "ground" reaction forces at points A and B pointed up toward...
We can solve for the maximum 5 lux illumination distance with the above equation.
E = 10.76*(35,000/d^2)
d = 275 feet (approximately).
However, the 5 lux illumination distance is not 275 feet. The 35,000 cd value is not an axial intensity value. It is at a point that is slightly down and to...
Homework Statement
I have a significant problem with the following excerpt from a general chemistry text:
Note that ON stands for oxidation number (state). The excerpt is with regard to polyatomic anions - specifically, chloride ion and its related polyatomic anions.
>It now follows that as...
Homework Statement
This is my prof's explanation of Diels-Alder ... below is the mechanism and some resonance structures he drew to explain the concerted movement of electrons to the class ...
Homework Equations
Nucleophiles attack electrophiles.
Electrons in HOMOs go into LUMOs.
The...
Homework Statement
The attempt at a solution
1) Is the above excerpt describing pi-backbonding? It seems to be describing some form of backbonding because the electron density is moving away from the positively charged metal cation (rather unexpected based on superficial Columbic analysis)...
Well, I didn't want to go through the entire mechanism from start to finish since the beginning isn't relevant. It all begins the same way - nucleophilic attack at the carbonyl carbon.
Homework Statement
Problem: I am told that the first mechanism is operative in saponification.
The Attempt at a Solution
However, this strikes me as wrong because the first mechanism involves the formation of dianion. Using hydroxide ion to abstract a proton and make that particular...
Yep, I realized that solvation is a factor. I mentioned this to my professor and although he did not outright disagree with me about solvation, he dismissed it as being basically too advanced for the students.
I could definitely see sterics having an effect on solvation of the conjugate base...
Homework Statement
How do sterics affect basicity?
Homework Equations
Sterics has to do with kinetics.
Basicity is a thermodynamic property.
Nucleophilicity is a kinetic property.
The Attempt at a Solution
So is the answer "sterics don't affect basicity"?
I can't see why sterics...
So if I'm understanding you correctly the reduction of H+ in water solution to hydrogen gas is dependent on the availability of protons. It is easier to take a positive charge from a positively charged molecule rather than a positive charge from a neutral molecule, so the reduction of H+ in...
Why not just take protons from water then? There are 50 plus moles of water even in most acidic solutions ... Excluding things like 18 M sulfuric acid.
Cool. So why does the potential decrease relative to the standard hydrogen electrode as the pH goes up for the oxidation of hydrogen protons? I'm guessing that it's easier taking hydrogen from hydronium ion in acidic solution than it is taking hydrogen from water in basic solution, since...
Sweet. Regarding the Nernst equation and how it predicts potential to decrease with increases in pH:
Is the protonation of oxygen dependent on kinetic or thermodynamic factors? I'm guessing thermodynamic factors because in more basic medium, the thermodynamic potential for protonation...
Homework Statement
Why is this true?
Why is it that the reduction of oxygen is more favored in acidic solution rather than in basic solution?
Homework Equations
Acids are proton donors.
The Attempt at a Solution
Does this have anything to do with the fact that the...
Does the polarity of the binary halogen acids increase or decrease down the group?
I have one argument for decrease based solely on electronegativity considerations.
I have one argument for increase based on orbital overlap and electron density. Taking electron density in an orbital to be...
Thank you for the thorough response. It seems that our textbooks greatly simplify naming considerations to picking out the longest chain. My teacher also changed the answer to 4-(1-chloroethyl)-4-methylheptane. Oh well.
My teacher insists the name of this compound is (2S)-chloro-3-methyl-3-propylhexane
Shouldn't it be 4-(1-chloroethyl)-4-methylheptane? (Ignore R,S configuration for now).
Chemoffice also tells me 4-(1-chloroethyl)-4-methylheptane.
I think it's the latter because I've consulted three...
Homework Statement
What if we stuck with the IUPAC name and called the isopropyl group a 1-methylethyl group? That would definitely reverse the alphabetical priorities; because the substituents here on the hydrocarbon are on equivalent positions, we must give the lower number to the...
It's because the d-orbitals aren't generally accessed by sulfur. The d-orbitals are too high in energy. So sulfur just sticks with structures that are best described using charge-separated Lewis structures.