I think an error could be to read the diffraction angle. Because people may read different angles, albeit with slight differences. And because the diffraction angle is related to the wavelength, can affect it.
To solve, using the conservation of energy:
so using the conservation of energy:
E'=- 0.74 MeV
But the energy sign has become negative. I also calculated for the first excited...
In "An Introduction to Nuclear Physics by W. N. Cottingham, D. A. Greenwood" for the surface area of an oblate ellipsoid, the following equation is written for small values of ε :
The book has said this without proof.
I found the following formula for the desired shape:
No matter how hard I...
I'm still confused. For example, in 'Introduction to Elementary Particles by Griffith', for relativistic collisions, the center of momentum frame is introduced to solve problems. But isn't the center of mass frame appropriate in relativistic collisions?
I came back.:smile: I still have a knot in understanding this exercise. :frown:
Now the values are almost equal. That is, the potential difference is equal to the mass difference. What exactly does this mean? That is, how do you analyze this?
Using the relation sent here and the following data, I obtained a value for the electric potential energy of the proton, which is:
1.6 * 10^ (-13) J
R= 8.7 * 10 ^ (-16) m
k= 9 * 10 ^ (19) Nm^2/c^2
Q= 1.6 * 10 (-19) c
What does this number say?
I do not really know the relationship between potential energy and mass difference.
Isn't the difference in mass of protons and neutrons due to their quarks? (the neutron is made of two down quarks and an up quark and the proton of two up quarks and a down quark.)