I really don't understand hypothesis testing.
How do I recognize which one is Ho and Ha in a problem?
Is there a particular trick to facilitate my lfie?
How can i proove if this line is perpendicular to this one?
Line
x=-2-4y, y=3-2t, z=1+2t
Plane
2x+y-z=5
I don't care that much about the answer, I want the procedure.
At first, i putted the first number in the frist row as 1.
so i get [1 1/3 1/3 1/3 0]
than i eliminate the 5 to make it a 0.
But its after that i got ****ed!
mayday!
Linear stuff: I never get the awnser...!
[3 1 1 1 0]
[5 -1 1 -1 0]
Where the variables are X1 X2 X3 X4.
I always get somethignt that is far away from the answer.
The answer should be x1= -s x2=-t-s x3=4s x4 = t
Help please!
Can anybody help me find the volume y=sinx, bounded by the y axis, and the line y=1. The axis of revolution is the line y=1.
I tried so many times and I can't find the correct answer, in the sheet it says (pie^2)/2 - 2pie
R is bounded by the curves y=(x-1)^2 and y=2(x-1). Axis of revolution: y-axis.
How am i supposed to do this. I know how to do the washer method, I know how to apply it when it is revolved arround the x-axis, but I don't know how to do it when it is the y axis. Can anybody explain to me the...
I don't know man, maybe the answer sheet is wrong. It says 9pie/4,as I mentionned before.
I tried, I had pie/2, and test it on graphmatica the program, and it gave something near it.
Here's a integral where I have to use trigonometric substitution but I can't get the right answer.
[int a=0 b=3] 1/(sqrt[9-x^2]) dx
I did the limit as t approches 3 from the left.
Then i did my trigonometric substitution, and it gives me arcsin(x/3).
Then i computed what i had...
Nice, i check it out on gragphmatica, and the graph of both seems to match the original function. Thanks dude, if i have a question i<ll comme back here :tongue:
I tried and it keeps giving me 0.
2[sqrt(abs(x-2))] from 1 to t and 2[sqrt(x-2)] from t to 3
(2[sqrt(abs(1-2))])-(2[sqrt(abs(t-2))])
and
(2[sqrt(abs(t-2))])-(2[sqrt(abs(3-2))])
(lim t->2+ (2[sqrt(abs(t-2))])-(2[sqrt(abs(1-2))]) )
+
(lim t->2-...
I've posted on Homeworks one of the number I did not understand. However, I would like to know the steps to calculate an improper integral of type 2. The type 2 is the one from constant a to constat b, not the one with inifnite.
Please tell me the steps the accomplish it. :smile:
I know...
I don't understand my Math Homework, here's the number that I don't get.
[int a=1 b=3] 1/(sqrt[abs(x-2)]) dx
sqrt = square root
abs = absolute value
Integral from 1 to 3
Can anyone explain this to me clearly, I'll really appreciate :smile:
Thanks