Is there any way which is more scientific to understand "a sudden discharge of accumulated sexual excitement"? Specifically, what is the "accumulated sexual excitement"?
Again this is not referring to any fluid transfer, but just the orgasm itself. It seems to me to be almost like a...
I'm sure this is a strange question, but I am really curious as to whether the human body can produce electromagnetic pulses. And particularly, whether an orgasm is a type of EMP.
Wikipedia says an orgasm is "a sudden discharge of accumulated sexual excitement". So is this discharge of...
Wow, I wish that were true!:sorry:
Every answer just leads to more questions. Therefore, I don't see my line of questioning ending anytime soon, but you have already done more than enough, so I will stop wasting your time.
Thanks for your help and your patience!:bow:
If I want more answers I...
I'm honestly not sure. I've seen astronauts or other things, like in the ISS, floating and it takes very little force to move something in a specific direction. When they are floating, they are moving a little, but it is hard to tell if it is from prior force applied. However, without a...
Darn, thought I had it!o_O
It depends on the mass right? ... but the mass is the same...
The acceleration includes direction, so won't it have a similar result as net force, because acceleration is happening in two different directions?
wait.. I understand that 2 opposite forces can create a...
Okay, so there is an initial force to the right and then a force from the left, meaning the net force is the larger force minus the smaller force. And in either case the net force will be less than the larger force, and mass will stay the same, so the acceleration must decrease. Since...
*BASKETBALL UPDATE*
So, I just came back from shooting around and playing a few games and, from the best I can tell, I think the power behind the shot may be about the same regardless of the hand motion, shooting hand coming up with the ball or shooting hand just meeting the ball at the peak...
I now realize that my question for basketball may be too complicated to answer due to the complexity of many factors. However, just so I walk away learning a little more about physics, here is a really simplified version of what I am wondering.
Does it takes more force to move X amount of mass...
Thanks, I saw the info!
I've been playing basketball for many years and I shoot fine, and like most people do. But what I am wondering about is whether I should be dribbling and then gathering with my off hand or my shooting hand. I always gather with my shooting hand, and from what I've seen...
Then considering a set shot, removing all other factors like jumping etc., and imagining a candy cane shaped path from the ground up, and releasing the ball at the peak or crest, ...is it possible that the vertical portion of the path is adversely affecting the forward momentum of the ball?
I enjoy playing basketball and I’m trying to figure out how to increase my range, so that I can shoot further. There are many contributing factors, but I’m curious how the movement of the ball and my arms contribute to how much power I can get behind the shot.
This is difficult to explain in...
Tulip mania was an economic bubble which occurred due to an sudden increase in demand and willingness to pay large sums of money for tulips. In these types of cases, the price of something may temporarily increase, but the bubble eventually pops, as it did with tulips, and the price returns to...
Good call! :biggrin:
Are you referring to K39 vs Ca40? If so, they are still separated to reach higher purity levels I guess, so it is not like comparing the raw elements, but it may be a step in the right direction.
However, the cost of K39 @ 7.90 Euros is still twice the cost of silver...
That's fine, if that is indeed the case, but there still must be a rational reason. So why are people willing to pay six times more for K41 in comparison with Ca44 or other similar isotopes?
If K41 is not particularly more difficult or time consuming to separate, and I'm not sure that it's...
Sorry, I'm not sure I understand what you mean by a difference of 8.
K41 is 145.5 Euros per mg and Ca44 is 24.75 Euros per mg. That's 120.75 Euros (roughly $140) per mg difference in price, with K41 being 6 times more expensive than Ca44.
Sorry, but I have one more question related to this topic. Can anyone tell me why potassium 41 seems to be much more expensive than isotopes of other elements of comparable purity and percentage of occurrence.
For example, according to this chart (Price list of electromagnetically separated...
Oh, good point! I forgot about inflation!
The text was last revised in 1961 which means $1 then is $9.30 now.
So the $11.75 listed is really $97.50 per Mg now, which is much closer to the current 145.5 EUR (164 USD), but still significantly cheaper. It is however more expensive than the guy...
Wow! Nice find!:woot:
So what would account for the difference in price? It looks like it used to be much cheaper. I would think that as technology has become more advanced the price would decrease, not increase. My only guess is that it has to do with the level of enrichment, which is listed...
Thanks for your reply :biggrin:
Companies like that typically ask for your company or institution name when requesting a quote, but I am just inquiring out of curiosity as an individual, which is why I was asking. I thought maybe someone else had purchased it in the past and could give me a...
Can anyone tell me what the commonly used methods of isotope separation are for Potassium 41? I know there are many different methods used for isotope separation, but I'm wondering which method is most practical (cheapest and purity) in the case of potassium, specifically K41.
Also roughly what...
I was researching cryogenic storage dewars and read that, "All dewars have walls constructed from two or more layers, with a high vacuum maintained between the layers. This provides very good thermal insulation between the interior and exterior of the dewar, which reduces the rate at which the...
Thanks for the info!
So my understanding was that all matter would revert to Fe-56, rather than Ni-62, even though Ni-62 has a higher binding energy. Wikipeida states this as being due to the competition between photodisintegration and alpha capturing during nucleosynthesis.
So does what you...
Sorry for my ignorance. What is the difference between 'donate' and 'give up'?o_O
I still can't understand why Fe would want to give up 3 electrons. So far I have only studied smaller elements (Ca and smaller) and everything made sense because, with the exception of hydrogen, all the elements...
I guess what was (is) confusing me is the different electron configurations for Fe ions.
I watched a video about it and my confusion is why Fe3+ is able to donate 3 electrons to form a compound like FeCl3 when it has 5 electrons in its outer shell (d)?
As I understand you are saying that above a certain pressure an atom of Fe-56 does become unstable.
In theory, is going beyond this critical pressure point what causes the collapse of an iron star into a neutron star?
I read that all matter in the universe, through fission or fusion, will eventually create 'iron stars' comprised of 56Fe, which will then eventually collapse into neutron stars and black holes.
Is it possible for two 56Fe atoms to fuse together?
As I understand they won't. So what happens when the two atoms undergo extreme heat/pressure? Do they break down into neutrons?
Thank you again for all your feedback! I'm grateful that everyone here takes the time to respond to my questions, seeing as how nobody is paid to do so. Any type of feedback is always valuable to me because there is always something I can learn from it. And even if I can't understand anything...
I saw on Wikipedia that Fe has both positive and negative oxidation states.
I know that Fe will willingly give up its 2 electrons to form an ionic bond with O for example, making it Fe+2.
1. But how can Fe+3 exist? This means it gives up three electrons right? Does this mean the Fe atoms...
I'm not sure why but I can't see the structure with that article either. Maybe you have to be logged in as well, or maybe I have no idea what I'm doing.o_O Anyway, I think I know what it looks like. Thanks again
Thanks! :woot:
1.) I don't have an account with this website so I can't see the structure.
What do the [brackets] around N2 mean? Does this represent a double covalent bond between the nitrogen atoms in comparison with an ionic bond between Ca and N2?
2.) Is it also possible for HK[N2] to...
*update: sorry this was a mistake (kind of)...:sorry:
I was thinking about the 2 nitrogen atoms having a double bond with each other and then an ionic bond with the Ca. Is this possible?
Got it! :biggrin:
So, if I understand correctly you are saying that there will most likely be a reaction between Cl2 and HK, which will produce HCl and KCl?
If my understanding is correct, the polar covalent bond in HCl creates a polar molecule because the molecule is unsymmetrical.
1. Does this mean that the partially positive H of one HCl molecule will be attracted to the partially negative Cl of another HCl molecule and vice versa, to create a...
Does anyone happen to know if Cl2+KH > KCl + HCl?
And if it does, what is the reasoning? Is it because Cl2 prefers an ionic bond rather than a covalent bond?
Got it! Thanks again :bow:
Is there anywhere you can go to see a list of 'known' reactions between compounds? Like the website I found before, but with real reactions...
So, just to be clear. Is there no reaction between HCl and NaCl? How can I know if a reaction will occur?
Is there any disassociation or maybe transfer of Cl- ions between HCl and NaCl?
If the answer is no reaction, then can we assume Cl2 + NaH will result in HCl and NaCl? How can we know...